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Shell Programming and Scripting

How to replace part of string?

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# 8  
Old 04-24-2019
Quote:
Originally Posted by vgersh99
simplified and fixed:
Code:
awk -F= -v var="$new_value" '/ABCD/ {$1= "=" var} 1' file > new_file

Not quite there $1 contains the variable name and is overwritten with "=" newvalue, try:

Code:
awk -F= -v var="$new_value" '/ABCD/ {$2 = var} 1' OFS== file > new_file

This User Gave Thanks to Chubler_XL For This Post:
green_k
# 9  
Old 04-24-2019
Quote:
Originally Posted by vgersh99
simplified and fixed:
Code:
awk -F= -v var="$new_value" '/ABCD/ {$1= "=" var} 1' file > new_file

ti works. thanks.
# 10  
Old 04-25-2019
Quote:
Originally Posted by Chubler_XL
Not quite there $1 contains the variable name and is overwritten with "=" newvalue, try:

Code:
awk -F= -v var="$new_value" '/ABCD/ {$2 = var} 1' OFS== file > new_file

Thanks.
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