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Passing Day in string

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# 8  
Old 02-07-2019
Quote:
Originally Posted by danielshell
Thank you, RudiC!

Code:
root:root> uname -a
HP-UX B.11.31 U ia64 0123365846 unlimited-user license

It is HP-UX, so it is kind of tough.. I am getting this error

Code:
root:> date +"%b %_d" -d "2 day ago"
 date: bad format character - _


Welcome.



The first thing I would try encountering that error message is relaunch the command without the _ and / or consult the man page. Having said that, I'm afraid that your date will fail on the -d option. So - rely on e.g. rdrtx1's proposal. Or - search these fora for "HP-UX" and "date" keywords.
This User Gave Thanks to RudiC For This Post:
danielshell
# 9  
Old 02-07-2019
Thank you so much!!! I will modify my script and run it for 3 days to validate that everything runs ok.
Appreciate it your help! I will keep you posted!
# 10  
Old 02-08-2019
I am new to shell programming, here is what I did.

Code:
#!/bin/sh

# Code is POSIX compliant


currentDate="$(date -R)"


counter=0

for word in $currentDate
do

  # We ignore the day of the week.
  if [ $counter -eq 0 ]
  then

    counter=$((counter+1))
    continue
  fi


  # We store the day of the month.
  if [ $counter -eq 1 ]
  then
    dayOfMonth=$word

    counter=$((counter+1))

    continue
  fi


# We store the name of the month.
  if [ $counter -eq 2 ]
  then
    month=$word

    break
  fi

done


echo "$month $dayOfMonth"


exit 0


It outputs:
Code:
Feb 08

From there, it remains to create the days you want, from this result.
This User Gave Thanks to johnprogrammer For This Post:
danielshell
# 11  
Old 02-08-2019
I completed the code:
Code:
#!/bin/sh

# Code is POSIX compliant

tput clear

currentDate="$(date -R)"


counter=0

for word in $currentDate
do

  # We ignore the day of the week.
  if [ $counter -eq 0 ]
  then

    counter=$((counter+1))
    continue
  fi


  # We store the day of the month.
  if [ $counter -eq 1 ]
  then
    dayOfMonth=$word

    counter=$((counter+1))

    continue
  fi

  # We store the name of the month.
  if [ $counter -eq 2 ]
  then
    month=$word

    break
  fi

done


dayOfMonth=$(echo "$dayOfMonth" | tr --delete 0)


day1="$month $((dayOfMonth-5))"

day2="$month $((dayOfMonth-4))"

day3="$month $((dayOfMonth-3))"


echo "day 1: $day1"
echo "day 2: $day2"
echo "day 3: $day3"


exit 0

It outputs:
Code:
day 1: Feb 3
day 2: Feb 4
day 3: Feb 5
[john@manjaromatepc Downloads]$

This User Gave Thanks to johnprogrammer For This Post:
danielshell
# 12  
Old 02-18-2019
I thought of a better way on this script (if it is possible)

Code:
lpstat -o |grep -v bytes |sort -nkb1

returns the outputs, i.e.

Code:
sld-8638            prod         priority 1  Feb 14 11:51
sld-8719            prod         priority 1  Feb  8 09:24
sld-8782            prod         priority 1  Feb 14 12:13
sld-8788            prod         priority 1  Feb 14 12:14
sld-8790            prod         priority 1  Feb 14 12:14
sld-8800            prod         priority 1  Feb 14 12:18
sld-8961            prod         priority 1  Feb 16 14:53
... <snipped> ....

If we can add
Code:
mtime +3

like:

Code:
lpstat -o |grep -v bytes |sort -nkb1 | ?? mtime +3 ?? |awk {'print $1'} > cleanuplist.txt

, the script can be a whole lot simpler and better.

But, HP-UX doesn't have mtime..

Code:
root:> man mtime
No manual entry for mtime.

Is there a way that we can add the equivalent of "mtime +3" to
Code:
lpstat -o |grep -v bytes |sort -nkb1 | ?? mtime +3 ?? |awk {'print $1'} > cleanuplist.txt

?

Thank you so much!
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