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ksh String Manipulation - removing variables from within a variable

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# 15  
Old 02-01-2019
I like these ones in particular:


Code:
echo ${array[@]//g}
john paul eore rino
echo ${array[@]//[og]}
jhn paul ere rin

This User Gave Thanks to RudiC For This Post:
apmcd47
# 16  
Old 02-01-2019
Back to question#1.
If you really want simple strings, you need nested for loops.
Still things look easy if you hide the complexity in a function.
Code:
#!/bin/sh
NAMES_without(){
  for i in $NAMES
  do
    for j
    do
      [ "$i" = "$j" ] && continue 2
    done
    echo "$i"
  done
}

NAMES="John
Paul
George
Ringo"
EXCLUDE_NAMES="Ringo
Paul"
NAMES=$(NAMES_without $EXCLUDE_NAMES)
echo "$NAMES"

Output is
Code:
John
George

As you see, I have taken a newline as separator. Often this is handier than a space.
# 17  
Old 02-01-2019
@MadeInGermany: Why should multiple / repeated "Pattern Substitution" not work on simple strings? No loop needed. With the variables as defined in post #16 (and falling back to bash and it's extglob / extended pattern matching):


Code:
echo "${NAMES//@(${EXCLUDE_NAMES//$'\n'/|})}"
John

George

You may apply another expansion to remove duplicate separators.
This User Gave Thanks to RudiC For This Post:
MadeInGermany
# 18  
Old 02-04-2019
@RudiC, that seems to only work in an interactive shell.?
# 19  
Old 02-04-2019
@MadeInGermany: no, works as well in a shell script. Don't forget to
Code:
shopt -s extglob

prior to executing the (complex) expansion.


Code:
echo $BASH_VERSION 
4.4.19(1)-release

This User Gave Thanks to RudiC For This Post:
MadeInGermany
# 20  
Old 02-04-2019
Right, I forgot to set the extglob!
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