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Grep only words containing specific string

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# 1  
Old 01-25-2019
Grep only words containing specific string
Hello,
I have two files. All urls are space seperated.

source
Code:
http://xx.yy.zz http://df.ss.sd.xz http://09.09.090.01
http://11.22.33 http://canada.xx.yy http://01.02.03.04 
http://33.44.55 http://98.87.76.65 http://russia.xx.zz
http://aa.tt.xx.zz http://1w.2e.3r.4t http://china.rr.tt

readfile
Code:
canada
87.76
2e
df

Expected output
Code:
http://canada.xx.yy
http://98.87.76.65
http://1w.2e.3r.4t
http://df.ss.sd.xz

What I tried:

Code:
while read -r line
do
grep -Po '$line\K[^ ]+' source
done <readfile > output
exit 0


For this case, could you please let me know how I may get any word containing given string in each line?

Thank you
Boris
# 2  
Old 01-25-2019
Code:
grep -of <(sed 's/.*/\\S*&\\S*/' readfile) source

This User Gave Thanks to nezabudka For This Post:
baris35
# 3  
Old 01-25-2019
How about - given your system / shell (which you fail to mention) provides "process substitution" -



Code:
grep -of <(sed 's/^/[^ ]*/; s/$/[^ ]*/' file2) file1
http://df.ss.sd.xz
http://canada.xx.yy
http://98.87.76.65
http://1w.2e.3r.4t

This User Gave Thanks to RudiC For This Post:
baris35
# 4  
Old 01-25-2019
Your own approach wasn't too far off. Be aware that single quotes prevent the shell from expanding variables, and that you'd need to extend the regex by adding provision for a prefix (like "http://").

Code:
while read -r line; do grep -Eo "[^ ]*$line[^ ]+" file1; done <file2
http://canada.xx.yy
http://98.87.76.65
http://1w.2e.3r.4t
http://df.ss.sd.xz

Last edited by RudiC; 01-25-2019 at 02:35 PM..
This User Gave Thanks to RudiC For This Post:
baris35
# 5  
Old 01-25-2019
Thank You nezabudka and RudiC.
Both work as expected.

Kind regards
Boris
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