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Debian, string in string.


 
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# 1  
Old 12-12-2018
Debian, string in string.

Example, check if user is in a group.

echo groups
Berty adm, dialout, cdrom, foo, foo

how to check that 'dialout' is in that output

I thought of awk '{print $x}' but x won't aways be the same.

Thanks.
# 2  
Old 12-12-2018
I am assuming
Quote:
$groups
has values
Code:
Berty adm, dialout, cdrom, foo, foo


a simple grep should get you

Code:
echo $groups |  grep dialout


with awk
Code:
echo $groups | awk '/dialout/{ print $0 }'

# 3  
Old 12-12-2018
With shell builtins:
Code:
case $groups in (*dialout*) echo "true";; esac

This is not precise though. Like the "grep" in the previous post. (The latter can be improved with "grep -w".)
# 4  
Old 12-13-2018
Using an interim variable:
Code:
ngroups=${groups#* }                                         # remove the prefix
[[ ,${ngroups// /}, == *,dialout,* ]] && echo yes || echo no # remove all other spaces; add , to beginning & end

You can use if instead of the && ... || construct I used above. Or you can put it in MadeInGermany's case statement:
Code:
case ,${ngroups// /}, in (*,dialout,*) echo "true";; esac

Andrew
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