Easy seq Question


 
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# 1  
Old 10-24-2018
Easy seq Question

Hi! I'm trying to do this:
1 -
2 -
3 -
4 -
5 -

I'm using seq for this:

seq 1 20 > filename.txt

How do I get the "-"? I've tried -f per man but can't get anything to work. Also, is there an easier or better way than using sequence? Thanks!
# 2  
Old 10-24-2018
the seq command doesn't do anything but generate sequences. How about this?

printf "%d -\n" `seq 1 20`

which amounts to printf "%d -\n" 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
This User Gave Thanks to Corona688 For This Post:
# 3  
Old 10-24-2018
After much experimenting with the -f feature I finally figured out how to trick it. It needs %.0f to make it print integers, followed by whatever string you want.

Code:
seq -f '%.0f -' 1 20

I suspect it's not really meant for that and might not work the same or reliably on other systems.
These 2 Users Gave Thanks to Corona688 For This Post:
# 4  
Old 10-24-2018
Thanks everyone! Both work great and I got a lesson in -f. :-)

------ Post updated at 05:53 PM ------

Sorry - Thanks Corona688! Didn't notice until now that both posts were from you. :-)
# 5  
Old 10-24-2018
If you have two constant numbers then in bash (or ksh93 or zsh) you can do
Code:
printf "%d -\n" {1..20}

# 6  
Old 10-24-2018
Just for the fun of it - no seq, no "brace expansion":


Code:
yes - | sed '=' | sed 'N; s/\n/ /' | head -20
1 -
2 -
3 -
.
.
.
19 -
20 -

or
Code:
yes | sed '=' | sed 'N; s/\ny/ -/' | head -20

or
Code:
yes | sed '=' | sed 'N; s/\ny/ -/; 40q'


EDIT: or - höhöhö -

Code:
yes - | cat -n | head -n20


Last edited by RudiC; 10-24-2018 at 03:20 PM..
# 7  
Old 10-31-2018
Not the most elegant, but for sure one of - if not "The" - most intuitive & easy to read and maintain :


Code:
 seq 1 20 | sed 's/$/ -/'


Last edited by ctsgnb; 10-31-2018 at 07:12 AM.. Reason: Just a little adjustment
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