awk conditional operators- lookup value in 2nd file
I use conditional operators alot in AWK to print rows from large text files based on values in a certain column. For example:
Code:
awk -F '\t' '{ if ($1 == "A" || $1 == "C" ) print $0}' OFS="\t" file1.txt > file2.txt
In this case every row is printed from file1 to file2 for which the column 1 value in file1 is either A or C.
This is fine if I'm working with a few conditional values in column 1 (2 in the above example), however, if there are many values to look up, say 40, it becomes cumbersome to write out 40 conditional values. In this case it would be more efficient to place all those conditional values in a separate file say file3. For example, file 3 could look like:
I modified a code that I was using for something else, and it seems to work fine for printing columns1 and column2 of file1 to file2, however, I need the column3 value also printed.
awk -F '\t' '
# when FNR==NR (only true for the FIRST file on cli),
# populate array f3 indexed by $1 (first field) in the file (file3)
# next - advance to the next input record/line in file3 without taking any
# following actions
FNR==NR {f3[$1];next}
# we get here for the file(s) following the first file on cli
# if $1 (first field) in the line/record is present in array f3,
# output the whole record in the current/f1 file
# this could be rewritten (long-hand) as $1 in f3 { print $0}
$1 in f3' OFS="\t" file3 file1.txt
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Hi All,
I have two files file1 and file2(lookup file).I need to map more than one keyfields of file1 with file2.how can we achieve it using awk.
file1(max 2.2 million records)
--------------------------
680720|680721|077
680720|680721|978
680721|680722|090
file2(no idea about the... (1 Reply)
10-22-2018
