How to remove leading and trailing spaces for variable in shell script?


 
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# 8  
Old 10-19-2018
I will try the above options and get back to you
# 9  
Old 10-19-2018
Still not clear to me. /bin/sh should be a POSIX conforming modern shell. Except I don't believe that is likely what you mean. Oh well.

This example is way less efficient than Don's suggestion, but works on modern UNIX systems and Linux AFAIK. In that sense it is pretty much safe.

Remove leading and trailing spaces at the same time:

Code:
f=" yyyy  "
# show variable using : to start and : to end
echo ":$f:"
: yyyy  :
# remove blanks
f=`echo "$f" | xargs`
# show variable using : to start and : to end
echo ":$f:"
:yyyy:

# 10  
Old 10-19-2018
Quote:
Originally Posted by pottic
2.6.32- Red hat version and I am using sh
"What model is your car?"

"Ford"

"Come again? What model is your car?"

"Blue"

It is not meaningful to say you're using sh. That is a generic term. There are many kinds of sh, and string substitution is one of the ways they specifically differ. If you don't know what your shell is, could you please find out?

Here's a generic method which ought to work in most kinds of sh, but has the severe side-effect of deleting your command-line parameters.

Code:
set -- $var
var="$1"


Last edited by Corona688; 10-19-2018 at 12:26 PM..
These 2 Users Gave Thanks to Corona688 For This Post:
# 11  
Old 10-19-2018
The issue is resolved.Thanks for the support
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