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Replace String without using sed

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# 1  
Old 10-08-2018
Replace String without using sed
Hi Team,

I have a file and need to replace string. Out of 20 rows, there is one row given below

Code:
$Paramsoqlfilter=Systemmodstamp > 1900-01-01T00:00:00.000Z

in a Shell Script, I have a variable
Code:
HIST_DATE="1900-01-01T00:00:00.000Z"
INC_DATE="2018-10-04T09:18:43.000Z"

Now I need to replace HIST_DATE with INC_DATE.

That mean, the string in a file should get INC_DATE like below

Code:
$Paramsoqlfilter=Systemmodstamp > 2018-10-04T09:18:43.000Z

Issue: sed -i not available. I'm suing korn shell

Can someone please help me?
# 2  
Old 10-08-2018
you don't need to have '-i' enabled sed to edit the file.
what's your file look like?
what do you have so far to edit the file so far (with or without sed)?
# 3  
Old 10-09-2018
Code:
HIST_DATE="1900-01-01T00:00:00.000Z"
INC_DATE="2018-10-04T09:18:43.000Z"

ex input_file << EDIT
1,$ s/$HIST_DATE/$INC_DATE/g
w!
EDIT

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jim mcnamara
# 4  
Old 10-09-2018
You can also use perl, which should be pre-installed on any *nix disto:

Code:
perl -p -i -e 's/$HIST_DATE/$INC_DATE/g' /path/to/file


That's may be easier to commit to memory if you're used to sed -i.
# 5  
Old 10-09-2018
Shell only:
Code:
while read -r line
do
  case $line in 
    (*"${HIST_DATE}") 
      line=${line#"${HIST_DATE}"}${INC_DATE}
    esac
  printf "%s\n" "$line"
done < file > file.new


--
bash / ksh93 / zsh:
Code:
while read -r line; do
  printf "%s\n" "${line/"${HIST_DATE}"/"${INC_DATE}"}"
done < file > file.new



----
Quote:
Originally Posted by Azrael
You can also use perl, which should be pre-installed on any *nix disto:

Code:
perl -p -i -e 's/$HIST_DATE/$INC_DATE/g' /path/to/file


That's may be easier to commit to memory if you're used to sed -i.
You would need to use double quotes for this to work..
Last edited by Scrutinizer; 10-09-2018 at 11:13 PM.. Reason: Added -r to read commands
# 6  
Old 10-11-2018
Quote:
You would need to use double quotes for this to work..
Maybe for the variable, but for straight substitution single quotes work just fine:

Code:
$ cat test
OK
$ perl -p -i -e 's/OK/NOTOK/' test
$ cat test
NOTOK

# 7  
Old 10-11-2018
Hi, with sed without -i :
file to modify:
Code:
$ cat /tmp/file.tst 
$Paramsoqlfilter=Systemmodstamp > 1900-01-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-01-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-01-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-01-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z

Code:
$ HIST_DATE="1900-01-01T00:00:00.000Z"
$ INC_DATE="2018-10-04T09:18:43.000Z"
$ exec 3</tmp/file.tst 
$ rm /tmp/file.tst 
$ sed -e "s/${HIST_DATE}/$INC_DATE/" <&3 >/tmp/file.tst
$ exec 3<&-

Code:
$ cat /tmp/file.tst 
$Paramsoqlfilter=Systemmodstamp > 2018-10-04T09:18:43.000Z
$Paramsoqlfilter=Systemmodstamp > 2018-10-04T09:18:43.000Z
$Paramsoqlfilter=Systemmodstamp > 2018-10-04T09:18:43.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 2018-10-04T09:18:43.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z
$Paramsoqlfilter=Systemmodstamp > 1900-02-01T00:00:00.000Z

Regards.
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