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Multiple regex in sed

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# 1  
Old 09-08-2018
Multiple regex in sed
I am using the following sed script to remove new lines (\r\n and \n), except from lines starting with >:

Code:
sed -i ':a /^>/!N;s/\r\n\([^>]\)/\1/;s/\n\([^>]\)/\1/;ta'

Is there a way to include both \r\n and \n in one regex to avoid the second substitute script (s/\n\([^>]\)/\1/)?
# 2  
Old 09-08-2018
Give it a try as \r?\n
Last edited by Aia; 09-09-2018 at 03:55 AM.. Reason: grammar correction
# 3  
Old 09-08-2018
This did not work:

Code:
sed ':a /^>/!N;s/\r\n?\n\([^>]\)/\1/;ta'

Or this:

Code:
sed ':a /^>/!N;s/\r?\n\([^>]\)/\1/;ta'

# 4  
Old 09-09-2018
Try:

GNU sed:
Code:
sed ':a /^>/!N;s/\r\?\n\([^>]\)/\1/;ta' file

Code:
sed ':a /^>/!N;s/\r\{0,1\}\n\([^>]\)/\1/;ta' file

Code:
sed -r ':a 1!N;s/\r?\n([^>])/\1/;ta' file




---
Note:
The above approaches will not work if there is a carriage return on the last line
Instead try this:
Code:
sed -r ':a 1!N;s/\r$|\r?\n([^>])/\1/g;ta' file

Last edited by Scrutinizer; 09-09-2018 at 04:26 AM..
This User Gave Thanks to Scrutinizer For This Post:
Xterra
# 5  
Old 09-09-2018
Thanks a TON! That worked like a charm
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