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awk variable into shell command "date -d": possible...?

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# 1  
Old 06-12-2018
awk variable into shell command "date -d": possible...?
Hello, there!
I am trying to pass an awk variable into a shell command ['date'] in order to collect the result into an awk variable; in Bash it does work, as in:

v='2'; date -d "now + $v weeks"

But in awk it does not, as in:

v="2"
"date -d 'now + v weeks'" | getline newdate
close ("date -d 'now + v weeks'")
print newdate

Does anyone have any ideas as to why that is so and/or whether it can be done as I need it?
Thank you all, in advance.
Last edited by fbird3; 06-12-2018 at 05:01 PM..
# 2  
Old 06-12-2018
Code:
v=2
awk -v newdate="$(date -d 'now + $v weeks')" '{print newdate}' myFile

This User Gave Thanks to vgersh99 For This Post:
richardsantink
# 3  
Old 06-12-2018
Or, to show how it can be done within awk itself:
Code:
awk 'BEGIN{v=2; cmd="date -d \"now + " v " weeks\""; cmd | getline newdate; close(cmd); print newdate}'

The way of quoting is different than in shell..

Or if you put it in a file file.awk:
Code:
BEGIN {
  v=2
  cmd="date -d 'now + " v " weeks'"
  cmd | getline newdate
  close(cmd)
  print newdate
}

Code:
awk -f file.awk

Last edited by Scrutinizer; 06-12-2018 at 05:10 PM..
# 4  
Old 06-12-2018
That's exactly what I was looking for.
Thanks a bunch!
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