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sed find multiple expressions plus next next line

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# 1  
Old 06-12-2018
Hammer & Screwdriver sed find multiple expressions plus next next line
Hello
I am trying to write sed code where it will look through the text for lines with specific expression "Started by user" and when found, will also add the following line, and also lines with another expression "Finished:"


Code:
sed -n '/Started by user/, +1p, /Finished:/' "${OUTPUT_DIR}/all_job_output"  > ${OUTPUT_DIR}/all_job_outputNew

I would appreciate your help, thank you
# 2  
Old 06-12-2018
Welcome to the forum.


Does the above work, or what goes wrong? And, add some sample input data plus your OS, shell, and sed versions.
# 3  
Old 06-12-2018
Hi yes it goes wrong
Code:
sed: -e expression #1, char 23: extra characters after command

It works if I only run first part without: , /Finished:/
Tried already without coma, with d; but also fails.

I am running it on Centos7 through Jenkins. GNU bash 4.2.46 x86_64, sed 4.2.2

---------- Post updated at 04:29 PM ---------- Previous update was at 03:51 PM ----------

Got It. Took me several hours but here it is:

Code:
sed -n '/\(Started by\|Building in\|Finished:\)/p' ${OUTPUT_DIR}/all_job_output > ${OUTPUT_DIR}/all_job_outputNew

Instead of doing plus one line I have searched for 3rd expression "Building in"

Thanks anyway.
Last edited by dlesny; 06-12-2018 at 11:52 AM.. Reason: added sed version
This User Gave Thanks to dlesny For This Post:
RudiC
# 4  
Old 06-12-2018
Thanks for sharing.



There were two things wrong with your first command: a , in lieu of a ; , and a p command missing after second address expression. Try

Code:
sed -n '/Started by user/, +1p; /Finished:/p' file

Please not the +1 address form is not standard but a GNU extension.
This User Gave Thanks to RudiC For This Post:
dlesny
# 5  
Old 06-12-2018
Thank you! Awesome Smilie
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