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# 1  
Old 05-03-2018
Rename multiple files in one go

OS : Oracle Linux 6.8
shell : bash

As shown below, I have multiple files like below (query1-extract_aa, query1-extract_ab, query1-extract_ac, ....)

Code:
$ ls -l
total 235680
-rw-rw-r-- 1 reportusr reportusr  30M May  3 11:25 query1-extract_aa
-rw-rw-r-- 1 reportusr reportusr  30M May  3 11:25 query1-extract_ab
-rw-rw-r-- 1 reportusr reportusr  30M May  3 11:25 query1-extract_ac
-rw-rw-r-- 1 reportusr reportusr  30M May  3 11:25 query1-extract_ad
-rw-rw-r-- 1 reportusr reportusr  30M May  3 11:25 query1-extract_ae
-rw-rw-r-- 1 reportusr reportusr  30M May  3 11:25 query1-extract_af
-rw-rw-r-- 1 reportusr reportusr  30M May  3 11:25 query1-extract_ag
-rw-rw-r-- 1 reportusr reportusr  22M May  3 11:25 query1-extract_ah

I want to append .txt to the end of these filenames , so that
Code:
query1-extract_aa will be renamed to query1-extract_aa.txt
query1-extract_ab will be renamed to query1-extract_ab.txt
query1-extract_ac will be renamed to query1-extract_ac.txt
    .
    .
    .
etc...

How can I do this in bash in one go ?
# 2  
Old 05-03-2018
You can't.
In bash you'll need a loop to rename every single file.
You may want to consider the (perl?) rename tool.
This User Gave Thanks to RudiC For This Post:
# 3  
Old 05-03-2018
My for loop (shown below) deleted all the files instead of renaming it Smilie

Any idea how I can do this correctly using a for loop (or any loop) ?
And how did my files get removed with the below mv command ?

Code:
$ ls -l
total 235680
-rw-rw-r-- 1 reportusr reportusr 31259250 May  3 11:25 query1-extract_aa
-rw-rw-r-- 1 reportusr reportusr 31198180 May  3 11:25 query1-extract_ab
-rw-rw-r-- 1 reportusr reportusr 31264556 May  3 11:25 query1-extract_ac
-rw-rw-r-- 1 reportusr reportusr 31246721 May  3 11:25 query1-extract_ad
-rw-rw-r-- 1 reportusr reportusr 31215875 May  3 11:25 query1-extract_ae
-rw-rw-r-- 1 reportusr reportusr 31172285 May  3 11:25 query1-extract_af
-rw-rw-r-- 1 reportusr reportusr 31189621 May  3 11:25 query1-extract_ag
-rw-rw-r-- 1 reportusr reportusr 22774687 May  3 11:25 query1-extract_ah
$
$
$ for i in query1-extract* ; do mv $i ${1}.txt; done
$ ls -lh
total 0
$

# 4  
Old 05-03-2018
Quote:
Originally Posted by kraljic
My for loop (shown below) deleted all the files instead of renaming it Smilie

Any idea how I can do this correctly using a for loop (or any loop) ?
And how did my files get removed with the below mv command ?

Code:
$
$ for i in query1-extract* ; do mv $i ${i}.txt; done
$ ls -lh
total 0
$

You used ${1} instead of ${i}

Andrew
This User Gave Thanks to apmcd47 For This Post:
# 5  
Old 05-03-2018
This is why you always do 'echo mv' on the first try. Better yet, take a backup before you do a batch rename. Consequences can be large.
This User Gave Thanks to Corona688 For This Post:
# 6  
Old 05-03-2018
after the first for...mv run when all files disappeared there should be a file in the directory called .txt (since $1 was not set) which is a copy of the last file on the list (query1-extract_ah). ls -al should show it.
This User Gave Thanks to rdrtx1 For This Post:

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