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awk script row to column


 
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# 1  
awk script row to column

Hi..

I have data :
Code:
Report testing1 20180419 08:00
Report testing2 20180419 07:35
Report testing 20180419 08:01
Source = data1
Report testing4 20180419 08:05
Source = data1
Report testing5 20180419 08:10
Source = data2
Report testing6 20180419 08:01
Report testing7 20180419 08:19
Report testing8 20180419 08:15
Source = data2

Output will be :
Code:
Report testing1 20180419 08:00
Report testing2 20180419 07:35
Report testing 20180419 08:01 Source = data1
Report testing4 20180419 08:05 Source = data1
Report testing5 20180419 08:10 Source = data2
Report testing6 20180419 08:01
Report testing7 20180419 08:19
Report testing8 20180419 08:15 Source = data2


Need help for the script awk.

Thanks all
# 2  
Code:
awk '
NR > 1 {printf ($0 ~ /^Source/) ? " " : "\n"; }
{printf $0}
END { if ($0 ~ /^Source/) print ""}
' data

This User Gave Thanks to rdrtx1 For This Post:
# 3  
Quote:
Originally Posted by rdrtx1
Code:
awk '
NR > 1 {printf ($0 ~ /^Source/) ? " " : "\n"; }
{printf $0}
END { if ($0 ~ /^Source/) print ""}
' data

i still didn't get it bro
# 4  
WHAT don't you get? Please be way more eloquent, showing non-satisfying output and error messages. rdrtx1's proposal works for me.
This User Gave Thanks to RudiC For This Post:
# 5  
Quote:
Originally Posted by RudiC
WHAT don't you get? Please be way more eloquent, showing non-satisfying output and error messages. rdrtx1's proposal works for me.
im so sorry my friend.. i just wrong copy paste..
its worked now..

thanks

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