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Complex: bash, using ANSI-C quotes in skript

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Top Forums Shell Programming and Scripting Complex: bash, using ANSI-C quotes in skript
# 1  
Old 02-21-2018
Complex: bash, using ANSI-C quotes in skript
Hello,

I hope someone can hep with this. I use a skript to send multiline Data to a Monitoring system. Bu I'm not able to use linebreaks or escape sequences.

The skript is simple like that:

Code:
#!/bin/bash
var="Erste Zeile \n zweite Zeile \n Dritter Teil" 
zabbix_sender -c /etc/zabbix/zabbix_agentd.conf -k "$zabitem" -o "$var"

This works - but without the linebreaks. If I use the command on commandline with:
Code:
zabbix_sender -c /etc/zabbix/zabbix_agentd.conf -k "$zabitem" -o $'Erste Zeile \n zweite Zeile \n Dritter Teil'

the result is fine!

The question ist - how can I use the $'string' with string as a variable (like $var).

Thank you and best regards
mpm
# 2  
Old 02-21-2018
try:
Code:
var='Erste Zeile \n zweite Zeile \n Dritter Teil'

Use of single quotes setting the variable so the backslash is not interpreted until the variable is used.
# 3  
Old 02-21-2018
Welcome to the forum.

Why not try
Code:
var=$'Erste Zeile \n zweite Zeile \n Dritter Teil'

# 4  
Old 02-21-2018
Quote:
Originally Posted by rdrtx1
try:
Code:
var='Erste Zeile \n zweite Zeile \n Dritter Teil'

Use of single quotes setting the variable so the backslash is not interpreted until the variable is used.
Thank you - but this does'n woked - the result was:

25409var

---------- Post updated at 08:22 AM ---------- Previous update was at 08:15 AM ----------

Quote:
Originally Posted by RudiC
Welcome to the forum.

Why not try
Code:
var=$'Erste Zeile \n zweite Zeile \n Dritter Teil'

thank you - but this only works with hardcoded Text. In my original Programm I've to use a variable and this is why i cant use this.
to be more percise:

Code:
#!/bin/bash 
vara="Erste Zeile \n zweite Zeile" #This Values are read form a File 
varb="\n Dritter Teil" 
var="$vara" "$varb"
zabbix_sender -c /etc/zabbix/zabbix_agentd.conf -k "$zabitem" -o "$var"

# 5  
Old 02-21-2018
Quote:
Originally Posted by mpmichael

Code:
#!/bin/bash 
vara="Erste Zeile \n zweite Zeile" #This Values are read form a File 
varb="\n Dritter Teil" 
var="$vara" "$varb"
zabbix_sender -c /etc/zabbix/zabbix_agentd.conf -k "$zabitem" -o "$var"

This seems to have several problems. First, you don't put newlines into your varb string. Second, you do the catenation wrong. Actually, you should have received an error from the line which assigns to var.

You say that vara is read from a file, so I assume that it already has the newlines in place (otherwise you do something wrong when reading it). As for varb and var:

Code:
vara=$(you_said_that_this_is_read_from_a_file_somehow)
varb=$'\n Dritter Teil'  # This is literal
var="${vara}$varb" # This catenates it

# 6  
Old 02-21-2018
Please give REPRESENTATIVE examples. The following works for me:
Code:
vara=$'Erste Zeile \n zweite Zeile'
varb=$'\n Dritter Teil'
var="$vara$varb"
echo "$var"
Erste Zeile 
 zweite Zeile
 Dritter Teil

# 7  
Old 02-21-2018
Quote:
Originally Posted by RudiC
Please give REPRESENTATIVE examples. The following works for me:
Code:
vara=$'Erste Zeile \n zweite Zeile'
varb=$'\n Dritter Teil'
var="$vara$varb"
echo "$var"
Erste Zeile 
 zweite Zeile
 Dritter Teil

Of course this works, but it is not what the OP wanted. Actually, there was nearly the same answer before, and he commented on this already. He said that if he specifies the variables literally (as you did), it works for him too, so this is obviously discussed already.

So I modified his last example to be more close to what he wanted. In what way do you think that it is not representative?
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