awk and sum


 
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# 8  
Old 01-22-2018
Code:
awk '
{
   w=$1; sub("[.].*", "", w);                                                      # strip first word
   if(! a[w]) {b[c++]=w; g=0;}                                                     # if word not read before load into word counter (keep the order read); reset gigabit sum;
   a[w]=a[w] $0 ",";                                                               # concatenate line string into word array
   if ($NF ~ /[0-9]*GB$/) {l=$NF; gsub("[^0-9]", "", l); s[w]=(g+=l);}             # strip number from last word; add value to sum for word
}
END {
   for (i=0; i<c; i++) {                                                           # loop for words read
      print a[b[i]] ((a[b[i]] ~ /snapshot/) ? "" : "nosnap,") "sum-" s[b[i]] "GB"; # print word array line stored, add "nosnap" if not found, sum for word in array
   }
}
' datafile

This User Gave Thanks to rdrtx1 For This Post:
# 9  
Old 01-22-2018
Another approach:
Code:
awk '
{
  split($1,F,".")
  i=F[1]
  A[i]=A[i] $0 ","
  T[i]+=$2
}
END {
  for(i in A)
    printf "%ssum-%sGB\n",A[i],T[i]
}
' file

But you did not answer one of Don Cragun's questions in post #2
Quote:
Originally Posted by Don Cragun
[..]
Are all numbers to be added given as "GB" values? Or could "KB", "MB", "TB" and/or other multipliers be present?
This is quite essential, because the approaches in this thread will be fail if the file can also contain KB, MB or TB values.
This User Gave Thanks to Scrutinizer For This Post:
# 10  
Old 01-22-2018
Quote:
Originally Posted by Scrutinizer
Another approach:
Code:
awk '
{
  split($1,F,".")
  i=F[1]
  A[i]=A[i] $0 ","
  T[i]+=$2
}
END {
  for(i in A)
    printf "%ssum-%sGB\n",A[i],T[i]
}
' file

But you did not answer one of Don Cragun's questions in post #2

This is quite essential, because the approaches in this thread will be fail if the file can also contain KB, MB or TB values.
The value will be in GB only
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