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How to print the specific part of the file name with file creation date?

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Top Forums Shell Programming and Scripting How to print the specific part of the file name with file creation date?
# 1  
Old 01-18-2018
How to print the specific part of the file name with file creation date?
Hello Folks,

I have an requirement, where i need to get total count of the file based on creation date with there filename selected pattern.

Filename: MobileProtocol.20171228T154200.157115.udr

I want to get the count of files created on each day based on a pattern find.


Code:
find . -type f -name "MobileProtocol.20171228T*" -printf '%TY-%Tm-%Td\n'|sort | uniq -c

Output is :

Code:
 1686 2017-12-28 
 287 2017-12-30
   1 2018-01-01
   1 2018-01-02
   2 2018-01-03
   1 2018-01-05
   2 2018-01-06
   3 2018-01-07
   1 2018-01-08
   1 2018-01-09
   1 2018-01-10
  35 2018-01-11

I want print pattern of the files too in my script.
Kindly guide and help me.

Output looking for is :

Code:
1686 2017-12-28 20171228  <--- from file pattern
 287 2017-12-30 20171228
   1 2018-01-01 20171228
   1 2018-01-02 20171228
   2 2018-01-03 20171228
   1 2018-01-05 20171228
   2 2018-01-06 20171228
   3 2018-01-07 20171228
   1 2018-01-08 20171228
   1 2018-01-09 20171228
   1 2018-01-10 20171228
  35 2018-01-11 20171228

Moderator's Comments:
Mod Comment Please use CODE tags (for data as well!) as required by forum rules!
Last edited by rbatte1; 01-18-2018 at 10:12 AM.. Reason: Added CODE tags.
# 2  
Old 01-18-2018
Code:
v=20171228 ; find . -type f -name "MobileProtocol.${v}T*" -printf '%TY-%Tm-%Td '${v}'\n'| sort | uniq -c

This User Gave Thanks to rdrtx1 For This Post:
sadique.manzar
# 3  
Old 01-18-2018
Try
Code:
find . -type f -name "MobileProtocol.20171228T*" -printf '%TY-%Tm-%Td %p\n' | sed -r 's/T[0-9.]{14}udr//; s/ .*\./ /;' | sort -k1,1 | uniq -cw10

This User Gave Thanks to RudiC For This Post:
sadique.manzar
# 4  
Old 01-18-2018
here is the output now i am getting:

Code:
1649 2017-12-28 20171228
 499 2017-12-30 udr
   1 2017-12-31 udr
   1 2018-01-01 udr
   1 2018-01-02 udr
   1 2018-01-05 udr
   1 2018-01-07 udr
   2 2018-01-10 udr
   5 2018-01-11 udr

---------- Post updated at 08:31 AM ---------- Previous update was at 08:17 AM ----------


What if I have multiple files with different pattern at the same place.
How will I implement that.

---------- Post updated at 08:39 AM ---------- Previous update was at 08:31 AM ----------


@RudiC and @ rdrtx1 Please reply.

@RudiC your command is giving the output like below:

Code:
1649 2017-12-28 20171228
499 2017-12-30 udr
1 2017-12-31 udr
1 2018-01-01 udr
1 2018-01-02 udr
1 2018-01-05 udr
1 2018-01-07 udr
2 2018-01-10 udr
5 2018-01-11 udr

Where I want 20171228 instead of every udr.
Kindly guide.
Last edited by rbatte1; 01-18-2018 at 10:14 AM..
# 5  
Old 01-18-2018
For Heaven's sake! My crystal ball is broken again! How can I see sadique.manzar's "multiple files with different pattern" now? How can I help him/her? And how and why can I find out why my [0-9.]{14} pattern doesn't match his/her
Code:
MobileProtocol.20171228T154200.157115.udr
                                 11111
                        12345678901234

filename?
Last edited by RudiC; 01-18-2018 at 10:24 AM..
This User Gave Thanks to RudiC For This Post:
sadique.manzar
# 6  
Old 01-18-2018
Quote:
What if I have multiple files with different pattern at the same place.
How will I implement that.
Code:
patterns="20171228 20171229"
for pattern in $patterns
do
   find . -type f -name "MobileProtocol.${pattern}T*" -printf '%TY-%Tm-%Td '${pattern}'\n'| sort | uniq -c
done

Last edited by rdrtx1; 01-18-2018 at 10:21 AM..
# 7  
Old 01-18-2018
@RudiC:
Code:
MobileProtocol.20171228T083500.18575.udr
MobileProtocol.20171228T043000.9955.udr
MobileProtocol.20171228T230700.103907.udr
MobileProtocol.20171228T095500.21219.udr
MobileProtocol.20171228T130000.156953.udr
MobileProtocol.20171228T182400.15272.udr
MobileProtocol.20171228T182500.15273.udr
MobileProtocol.20171228T082000.29941.udr
MobileProtocol.20171228T081800.156671.udr
MobileProtocol.20171228T082000.156673.udr
MobileProtocol.20171228T081900.156672.udr
MobileProtocol.20171228T151500.10084.udr
MobileProtocol.20171228T065000.26870.udr
MobileProtocol.20171228T170200.60932.udr
MobileProtocol.20171228T165400.60924.udr
MobileProtocol.20171228T165700.60927.udr
MobileProtocol.20171228T235900.104040.udr
MobileProtocol.20171228T125800.60688.udr
MobileProtocol.20171228T130000.60690.udr
MobileProtocol.20171228T125900.60689.udr

when i adjust the value [0-9.]{14} like 14 to 12 13 i get results for different pattern like "20171224" "20171227" and so on so how could i predict this value in general. ?
---------- Post updated at 09:24 AM ---------- Previous update was at 09:20 AM ----------

Code:
find . -type f -name "MobileProtocol.20171228T*" -printf '%TY-%Tm-%Td %p\n' | sed -r 's/T[0-9.]{13}udr//; s/ .*\./ /;' | sort| uniq -cw10

 1590 2017-12-28 20171228
  499 2017-12-30 20171228
    1 2017-12-31 20171228
    1 2018-01-01 20171228
    1 2018-01-03 20171228
    2 2018-01-05 20171228
    2 2018-01-06 20171228
    3 2018-01-07 20171228
    1 2018-01-11 20171228


 find . -type f -name "MobileProtocol.20171224T*" -printf '%TY-%Tm-%Td %p\n' | sed -r 's/T[0-9.]{12}udr//; s/ .*\./ /;' | sort| uniq -cw10

     2 2017-12-23 20171224
  2124 2017-12-24 20171224
     1 2017-12-27 20171224
     2 2017-12-31 20171224

how will i predict {12}udr in case for files pattern.


Moderator's Comments:
Mod Comment Thanks for trying to use tags - but don't "overtag". Your own text goes untagged, QUOTE tags for text cited from other sources.
Last edited by RudiC; 01-18-2018 at 10:32 AM.. Reason: Removed or changed QUOTE to CODE tags.
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