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Multidimensional array:awk error

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# 1  
Old 12-06-2017
Multidimensional array:awk error
Code:
 awk -F'\t' -v OFS='\t' '

 { if($2 in arr) {

         #print "Sahi", NR,arr[$2]
         for(k=2;k<=NF;k++){
#            sum[arr[$2]][k]+=$2
         }

 }
 else {
     arr[$2]=NR
     #print "awk",NR
     for (k=3;k<=NF ; k++){
         sum[NR][k]=$k
     }
 }


 }

 #-------------------
# END{
#        for (k in arr){
#            printf k"\t"
#            for(z=3;z<=NF;z++){
#                printf sum[arr[k]][z]"\t"
#            }
#            print "\n"
#        }
 #    }
#--------------------------

 ' < header.txt

Error:
awk: line 15: syntax error at or near [

I want to sum columns if there's duplicate of row in column 2.


Input format:

Code:
ASPM    ASPM    6.667   6.482
LOC400861       LOC400861       6.669   6.647
ASPM    ASPM    0.001   0.002

Outout:
Code:
ASPM    ASPM    6.668   6.484
LOC400861       LOC400861       6.669   6.647

Summed columns for ASPM

For the time being I've excluded header from input file. In future I'd like to process file as is and tweak awk code for it. Smilie

But for now I'd like to fix error for multi-D array.

---------- Post updated at 05:39 PM ---------- Previous update was at 05:17 PM ----------

I fixed for error but I get the line printed twice:

Code:
awk -F'\t' -v OFS='\t' '

 { if($2 in arr) {
         for(k=2;k<=NF;k++){
             sum[arr[$2],k]= $k + sum[arr[$2],k]
         }

 }
 else {
     arr[$2]=NR
     for (k=3;k<=NF;k++){
         sum[NR,k] = $k;
     }
 }
 }

 #-------------------
 END{
         for (k in arr){
             printf k"\t"
             for(z=3;z<=NF;z++){
                 printf sum[arr[k],z]"\t"
             }
             printf"\n"
         }
    }
#--------------------------

 ' < header.txt

output:
Moderator's Comments:
Mod Comment Please use CODE tags (not QUOTE tags) when displaying sample input and output as well as when displaying code segments.
Last edited by Don Cragun; 12-07-2017 at 01:10 AM.. Reason: Change QUOTE tags to CODE tags.
# 2  
Old 12-06-2017
I'm not sure your field delimiter is space or tab from your post, which can be fixed easily. I assumed it is space for my try:
Code:
awk -v OFS="\t"  '{A[$2]+=$3; B[$2]+=$4}END{for( i in A) print i, i, A[i], B[i]}'  < head.txt

Output:
Code:
LOC400861    LOC400861    6.669    6.647
ASPM    ASPM    6.668    6.484

# 3  
Old 12-06-2017
Thanks for your reply.
For illustration I had put 4 columns. In file I've 366 columns hence I used multi-dimensional array.
# 4  
Old 12-07-2017
If you don't show us the real format of your input file(s) and show us the actual output you're trying to produce from that input, it is hard for us to guess at what might work for whatever you are trying to do.

Without knowing what operating system you're using, we can't know what extended features available in some versions of awk might be available for use in your script.

What do you expect to get when you calculate the sum ASPM + ASPM?

Is the data in all of your fields starting with field #3 through field #366 in floating point format with three digits after the decimal point? If not, what is the general format and what format should be used for the output?
# 5  
Old 12-07-2017
Notwithstanding Don Cragun's worthwhile questions, I don't think extended features necessary for this problem. Try (output formatting excluded here):
Code:
awk -F'\t' -v OFS='\t' '
        {arr[$2] = $1
         for (k=3; k<=NF; k++)  sum[arr[$2],k] += $k
        }
END     {for (k in arr) {printf "%s%s%s%s", arr[k], OFS, k, OFS
                         for (z=3; z<=NF; z++)  printf "%s%s", sum[arr[k],z], (z==NF)?ORS:OFS
                        }
        }
' file
ASPM    ASPM    6.668    6.484
LOC400861    LOC400861    6.669    6.647

# 6  
Old 12-07-2017
Quote:
Originally Posted by RudiC
Notwithstanding Don Cragun's worthwhile questions, I don't think extended features necessary for this problem. Try (output formatting excluded here):
Code:
awk -F'\t' -v OFS='\t' '
        {arr[$2] = $1
         for (k=3; k<=NF; k++)  sum[arr[$2],k] += $k
        }
END     {for (k in arr) {printf "%s%s%s%s", arr[k], OFS, k, OFS
                         for (z=3; z<=NF; z++)  printf "%s%s", sum[arr[k],z], (z==NF)?ORS:OFS
                        }
        }
' file
ASPM    ASPM    6.668    6.484
LOC400861    LOC400861    6.669    6.647

Thanks for the reply.
Do you mind explaining:

Code:
(z==NF)?ORS:OFS

# 7  
Old 12-07-2017
man awk:
Quote:
5. Expressions and operators
The expression syntax is similar to C. . . .
conditional ? :
The logical expression in front of the ? is evaluated; if TRUE, the value of the expression between that and the : is the result to be used / assigned, if FALSE, the trailing one. Available in many other languages and shells as well.
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