Shell Programming and Scripting

syntax error near unexpected token `-u'

awk: cmd. line:10:                                 cmd = "echo \"Found " p_counter[k] " instances of " k " running\"
awk: cmd. line:10:                                                                                       ^ unterminated string

cnt=$(ps -u abcd | )
if [[ $cnt -gt 1 ]]; then
  echo "job runing longtime"
  exit 1
fi;

cmd = "echo \"Found " p_counter[k] " instances of " k " running\" 
                                                                                             ^ unterminated string

ps -u abcd -o comm= | awk '++s[$1]==10'

ps -u abcd -o comm= | awk '($1=="a.ksh" || $1=="d.ksh") && ++s[$1]==10'

 -o comm=

jobs=$(ps -u abcd -o comm= | awk '($1=="a.ksh" || $1=="d.ksh") && ++s[$1]==10')
if [[ -n "$jobs" ]]
then
  printf "jobs runing longtime:\n%s\n" "$jobs"
  exit 1
fi

ps

ps -opid,tty,time,comm

ps -opid,ppid,euid,comm

ps -opid=,ppid=,args=  # right
ps -opid,ppid,args=    # wrong, will only suppress the COMMAND heading

  
 jobs=$(ps -u abcd -o comm= | awk '($1=="a.ksh" || $1=="d.ksh") && ++s[$1]==10')
if [[ -n "$jobs" ]]
then
  printf "jobs runing longtime:\n%s\n" "$jobs"
  exit 1
fi

ps -u abcd -o comm= | awk '++s[$1]==10'

/usr/local/ksh/d.ksh 
/usr/ka/ksh/ab.java 
/usr/na/ksh/abc.perl

ps -u abcd -o pid= -o args=