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find -exec How to add additional parameter when calling a funtion

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# 1  
Old 10-09-2017
find -exec How to add additional parameter when calling a funtion
Hello

Current working script is :
Code:
#
# my_script  BEGIN
#

function a_function {

FIRST_PARAM="$1"

DO_SOMETHING "$FIRST_PARAM"

}

export -f  a_function

START_HERE="/home/some_user/Documents"
find $START_HERE"  -exec bash -c 'a_function "$0" ' {}   \;

#
# my_script  END
#

What I need is to have two more parameters in the called function :
Code:
#
# my_script_not working  BEGIN
#

function a_function {

FIRST_PARAM="$1"
SECOND_PARAM="$2"
THIRD_PARAM="$3"

DO_SOMETHING "$FIRST_PARAM" "$SECOND_PARAM" "$THIRD_PARAM"

}

export -f  a_function

START_HERE="/home/some_user/Documents"
VARIABLE_1="VALUE_1"
VARIABLE_2="VALUE_2"

find $START_HERE"  -exec bash -c 'a_function "$0" ' {}  "$VARIABLE_1"   "$VARIABLE_2" \;

#
# my_script_not working   END
#

I have tried to replace " by '
I have tried to remove or not "$0"
I have tried to put "$VARIABLE_1" "$VARIABLE_2" before or after {}

Any help is welcome
# 2  
Old 10-09-2017
Check your quoting... i.e. double quote the entire construct.
# 3  
Old 10-09-2017
Quote:
Originally Posted by RudiC
Check your quoting... i.e. double quote the entire construct.
I tried different things but no way.

Code:
#find $START_HERE" -exec bash -c 'a_function "$0" {}  $VARIABLE_1  $VARIABLE_2' \; 

#find $START_HERE" -exec bash -c 'a_function {}  $VARIABLE_1  $VARIABLE_2' \; 

#find $START_HERE" -exec bash -c 'a_function ' "$VARIABLE_1" "$VARIABLE_2" _ {} \; 

#find $START_HERE" -exec bash -c 'a_function  "$0" "$VARIABLE_2"  "$VARIABLE_1"'  _ {} \; 

#find $START_HERE" -exec bash -c 'a_function {}  "$VARIABLE_2"  "$VARIABLE_1"' \; 

#find $START_HERE" -exec bash -c 'a_function '  "{} $VARIABLE_2  $VARIABLE_1" \;

#find $START_HERE" -exec bash -c 'a_function  "$VARIABLE_2"  "$VARIABLE_1"'  __ {}  \;

#find $START_HERE" -exec bash -c 'a_function  "$0" '  "{}  $VARIABLE_2  $VARIABLE_1" \;

#find $START_HERE" -exec bash -c 'a_function  '  "{}  $VARIABLE_2  $VARIABLE_1" \;

#find $START_HERE" -exec bash -c 'a_function  '  {}  "$VARIABLE_2"  "$VARIABLE_1"  \;

#find $START_HERE" -exec bash -c 'a_function  '  "$VARIABLE_2"  "$VARIABLE_1"  {}  \;

#find $START_HERE"  -exec bash -c 'a_function  "$0" ' {}  "$VARIABLE_1"   "$VARIABLE_2" \;

# 4  
Old 10-09-2017
Hi.

Does this demonstration help?
Code:
#!/usr/bin/env bash

# @(#) s1       Demonstrate calling function from find -exec.

# Utility functions: print-as-echo, print-line-with-visual-space, debug.
# export PATH="/usr/local/bin:/usr/bin:/bin"
LC_ALL=C ; LANG=C ; export LC_ALL LANG
pe() { for _i;do printf "%s" "$_i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }
em() { pe "$*" >&2 ; }
db() { ( printf " db, ";for _i;do printf "%s" "$_i";done;printf "\n" ) >&2 ; }
db() { : ; }
C=$HOME/bin/context && [ -f $C ] && $C

function a_function {

FIRST_PARAM="$1"
SECOND_PARAM="$2"
THIRD_PARAM="$3"
fourth="$4"

echo DO_SOMETHING "$FIRST_PARAM" "$SECOND_PARAM" "$THIRD_PARAM" "$fourth"

}

pl " Current files f?:"
echo f?

export -f  a_function

START_HERE="/home/some_user/Documents"
VARIABLE_1="VALUE_1"
VARIABLE_2="VALUE_2"

pl " Results:"
# find $START_HERE"  -exec bash -c 'a_function "$0" ' {}  "$VARIABLE_1"   "$VARIABLE_2" \;
find .  -name 'f?' -exec bash -c "a_function $0 {}  $VARIABLE_1 $VARIABLE_2" \;

producing:
Code:
$ ./s1

Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution        : Debian 8.9 (jessie) 
bash GNU bash 4.3.30

-----
 Current files f?:
f1 f2 f3

-----
 Results:
DO_SOMETHING ./s1 ./f1 VALUE_1 VALUE_2
DO_SOMETHING ./s1 ./f2 VALUE_1 VALUE_2
DO_SOMETHING ./s1 ./f3 VALUE_1 VALUE_2

I used local directory with only f* files for brevity.

Best wishes ... cheers, drl
This User Gave Thanks to drl For This Post:
jcdole
# 5  
Old 10-10-2017
Quote:
Originally Posted by drl
Hi.

Does this demonstration help?
Code:
.....
.....
.....
find .  -name 'f?' -exec bash -c "a_function $0 {}  $VARIABLE_1 $VARIABLE_2" \;
.....
.....
.....

Ok that the trick.
But I have read that it is a bad idea to put {} between quote inside the caller ?

The following work also but the data return by {} is found at $0 in the function.
Code:
find .  -name 'f?' -exec bash -c "a_function  $VARIABLE_1 $VARIABLE_2"  {} \;

As far you know that, it is not a problem.

Thank you very much for helping.
# 6  
Old 10-10-2017
Hi, jcdole

You're welcome.
Quote:
Originally Posted by jcdole
But I have read that it is a bad idea to put {} between quote inside the caller ?
Where did you see this? The reading I have done suggests that {} may need to be placed within quotes to protect them from evaluation by the shell that is running the find command.

Best wishes ... cheers, drl
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