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Unable to read user input inside a loop

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Top Forums Shell Programming and Scripting Unable to read user input inside a loop
# 8  
Old 10-10-2017
Quote:
Originally Posted by Yoda
Can you please give me an example for this approach ?
Code:
CWD=$(pwd)
find data/ -type f \! -name test.tar | $AWK -F/ '{print $NF}' > ${CWD}/out.txt

while read entry
do
        echo "FILE_CURRENT_DIR:"$entry
        read -p 'Where do you want to copy $entry to? Please enter the complete directory location: ' -u 3 cppath
        echo "cp -R $entry $cppath/"
done 3<&0 < ${CWD}/out.txt

Code:
if [[ "$file" =~ "test.tar" ]] || [[ "$file" =~ "wow.tar" ]]
then
        continue
fi

Can you please tell me why is it failing when I try the same.

Code:
#!/bin/ksh
 . ./deploy.profile
set -x
found_flag=0
 searchdir=/tmp/moht
 CWD=$(pwd)
 
 find $searchdir"/PRESENT/data" -type f \! -name client.tar | $AWK -F/ '{print $NF}'  > ${CWD}/out.txt
 while IFS= read -r entry; do
  found_flag=0
if [ $found_flag -eq 0 ]; then
read -p "Where do you want to copy $entry to? Please enter the complete directory location: " -u 3 cppath
echo "cp -R $entry $cppath/"
cp -R $entry $cppath/
fi
  echo "Displaying the value of found_flag outside while loop:$found_flag"
 done 3<&0 < ${CWD}/out.txt

Error:
Quote:
+ found_flag=0
+ searchdir=/tmp/moht
+ + pwd
CWD=/tmp/moht
+ /usr/xpg4/bin/awk -F/ {print $NF}
+ find /tmp/moht/PRESENT/data -type f ! -name client.tar
+ 1> /tmp/moht/out.txt
+ 3<& 0 0< /tmp/moht/out.txt
+ read -r entry
+ IFS=
+ found_flag=0
+ [ 0 -eq 0 ]
+ read -p Where do you want to copy bingo.txt to? Please enter the complete directory location: -u 3 cppath
./readtest.sh[24]: read: no query process
+ echo cp -R bingo.txt /
cp -R bingo.txt /
+ cp -R bingo.txt /
cp: cannot access bingo.txt
+ echo Displaying the value of found_flag outside while loop:0
Displaying the value of found_flag outside while loop:0
+ read -r entry
+ IFS=
Hope this works with the KSH shell as well. Does it ?
# 9  
Old 10-10-2017
read is a shell built-in. The KSH built-in has different options to the Bash one. Is there any reason you changed your script from Bash to the Korn shell?
# 10  
Old 10-10-2017
Quote:
Originally Posted by Scott
read is a shell built-in. The KSH built-in has different options to the Bash one. Is there any reason you changed your script from Bash to the Korn shell?
The reason for changing to KSH from BASH was my bash version is 10 yrs old and I cannot update it as I m not the system admin. I need my variable to hold global value so it persists its value outside the loop. Refer to my thread here for details.

Can you propose any solution to the error I m getting as shown in RED BOLD this POST 8.
# 11  
Old 10-10-2017
You should at-least check the ksh manual, look at the read options and give it a try before posting question:-
Code:
man ksh

       read [ -ACprsv ] [ -d delim] [ -n n] [ [ -N n] [ [ -t timeout] [ -u unit] [ vname?prompt ] [ vname ... ]

So you should modify your code to:-
Code:
read -u 3 cppath?"Where do you want to copy $entry to? Please enter the complete directory location: "

# 12  
Old 10-10-2017
Quote:
Originally Posted by Yoda
You should at-least check the ksh manual, look at the read options and give it a try before posting question:-
Code:
man ksh

       read [ -ACprsv ] [ -d delim] [ -n n] [ [ -N n] [ [ -t timeout] [ -u unit] [ vname?prompt ] [ vname ... ]

So you should modify your code to:-
Code:
read -u 3 cppath?"Where do you want to copy $entry to? Please enter the complete directory location: "

I tried that but it gives me this error:

Code:
+ read -u 3?cppath Where do you want to copy bingo.txt to? Please enter the complete directory location:
./readtest.sh[25]: 3: is not an identifier

My ksh man page says:

Code:
     read [ -prsu[ n ] ] [ name?prompt ] [ name ... ]

Last edited by mohtashims; 10-10-2017 at 11:59 PM..
# 13  
Old 10-10-2017
I noticed the ? symbol right after the descriptor instead of variable name:-
Code:
+ read -u 3?cppath Where do you want to copy bingo.txt to? Please enter the complete directory location:
./readtest.sh[25]: 3: is not an identifier

Also you need to check your ksh version and manual for read options, I tested this code in ksh93 and it works fine:-
Code:
$ strings /bin/ksh | grep "[V]ersion"
@(#)$Id: Version AJM 93t+ 2010-06-21 $

# 14  
Old 10-11-2017
Hammer & Screwdriver
My ksh version is:

Code:
strings /bin/ksh | grep "[V]ersion"
@(#)Version M-11/16/88i

the variable name is cppath.

I tried
Code:
read -u 3 cppath "Where do you want to copy $entry to? Please enter the complete directory location: "

but this also fails with the same error : 3: is not an identifier. Can you tell me what syntax should I try ?
Last edited by mohtashims; 10-11-2017 at 12:36 AM..
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