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Replacing multiple asterisks in vi

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# 1  
Old 09-24-2017
Replacing multiple asterisks in vi
i need to replace all occurrences of "period asterisk" as it is shown in this:

Code:
blah blah .*:.*:.* blah blah

with:

Code:
[0-9][0-9]:[0-9][0-9]:[0-9][0-9]

so that the end result looks like this:

Code:
blah blah [0-9][0-9]:[0-9][0-9]:[0-9][0-9] blah blah

I tried different variations of the following but it didint work:

Code:
%s_ .*:.*:.* _ [0-9][0-9]:[0-9][0-9]:[0-9][0-9] _g

# 2  
Old 09-24-2017
Hi,

I just tried this in vim, and the following command worked for me:

Code:
1,$ s/\.\*/[0-9][0-9]/g

This turned the following string:

Code:
blah blah .*:.*:.* blah blah

into this:

Code:
blah blah [0-9][0-9]:[0-9][0-9]:[0-9][0-9] blah blah

Caveats: this was a quick one-liner in vim for iOS, so your mileage may vary as they say. But this appears to work for this very specific string in these very specific circumstances.
This User Gave Thanks to drysdalk For This Post:
SkySmart
# 3  
Old 09-25-2017
I think this works in all vi and vim variants and in all OSes.
Further it works in all sed versions, where the 1,$ (all lines) selector can be omitted because it is default.
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