Cron updates


 
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Top Forums Shell Programming and Scripting Cron updates
# 1  
Old 08-28-2017
Cron updates

This cmd will update the user's crontab with the quoted line.
But how to script the update using a previously stored variable?

Code:
crontab -l | awk '{print} END {print "* * * * * echo test >> /tmp/testing"}' | crontab

Code:
crontab -l | awk '{print} END {print "$storedvariable"}' | crontab

Does not get it done, nor does
Code:
...."\$stored...."


Moderator's Comments:
Mod Comment Please use CODE tags as required by forum rules!

Last edited by RudiC; 08-28-2017 at 01:49 PM.. Reason: Added CODE tags.
# 2  
Old 08-28-2017
The shell won't expand parameters or variable within single quotes. So - either use double quotes for the awk command but pay attention to escape the double quotes in the script,
Code:
crontab -l | awk "{print} END {print \"$storedvariable\"}"

or use the correct mechanism for awk: the -v option:
Code:
crontab -l | awk -v SV="$storedvariable" '{print} END {print SV}'


Why that complicated, by the way? How about
Code:
{ crontab -l; echo "$storedvariable"; }

This User Gave Thanks to RudiC For This Post:
# 3  
Old 08-28-2017
The final line....
Code:
crontab -l |awk -v CRON_add="$CRONadd" '{print} END {print CRON_add}' |crontab

...does do the deed
Thank you RudiC

---------- Post updated at 11:24 AM ---------- Previous update was at 11:20 AM ----------

RudiC, I am not following the line...
Code:
{ crontab -l; echo "$storedvariable"; }

# 4  
Old 08-28-2017
Try it, and compare the result to the others'. Dissect it. run it in parts.
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