Shell Programming and Scripting

Thanks, This works

---------- Post updated at 01:35 AM ---------- Previous update was at 01:34 AM ----------

Thanks this works fine

I doubt that it is working for all numbers below 99. And, you haven't told us what shell you're using to get these results. The above output is exactly what I would expect if you're using bash as your shell. As I explained in post #4 in this thread, bash treats 0120 (an octal number) as 80 (decimal).

Thanks a lot. This works

If you are in ksh (I don't think you ever said) you may be able to use typeset like this:-

Code:

typeset -Z7 LOGNUM
LOGNUM=95
((LOGNUM=$LOGNUM-1))
echo "$LOGNUM"

I get the output 0000094

I don't think this is available in bash, which is a little frustrating because it is so easy, however I'm sure there is a good reason. I have use this sort of thing frequently, so it would be know if there is a danger with it, hence why it has not made it into bash. If there is a neat way like this, I'd love to know it!



Kind regards,
Robin

Hi.

Also zsh, for a file z7:

Code:

zsh <<'EOF'
typeset -Z7 LOGNUM
LOGNUM=95
((LOGNUM=$LOGNUM-1))
echo "$LOGNUM"
EOF

producing:

Code:

$ ./z7
0000094

On a system like:

Code:

OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution        : Debian 8.8 (jessie) 
zsh 5.0.7

Best wishes ... cheers, drl