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Chaining together exec within find

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# 22  
Old 06-23-2017
It must run a BASH shell for each child.
# 23  
Old 06-23-2017
Quote:
Originally Posted by MadeInGermany
@Don, the -exec requires to set the argv[0] for a script interpreter like bash.
This is certainly true for all LUnix - otherwise process names would always be the script interpreter (e.g. bash).
For demonstration:
Code:
$ mkdir newdir
$ touch newdir/file{1,2,3}
$ find newdir -type f -exec bash -c '
echo "$@"
' {} +
 newdir/file2 newdir/file3
$ find newdir -type f -exec bash -c '
echo "$@"
' bash {} +
newdir/file1 newdir/file2 newdir/file3
$

In the first case the process name became newdir/file1.
Hi MadeInGermany,
I stand corrected. Note, however, that it isn't -exec that needs the (seemingly) extra argument in:
Code:
find path -type f -exec command initial_args {} +

The reason the args[0] value needs to be supplied is because the command being executed was a shell with initial_arguments being -c shell_commands argument... and sh -c needs a complete set of arguments; not just the positional parameters.

Trying to use -exec ls -ltr ls {} + or -exec rm rm {} + would not give you the results you want in those cases.
This User Gave Thanks to Don Cragun For This Post:
jim mcnamara
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