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Check Running Processes

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# 1  
Old 05-31-2017
Wrench Check Running Processes
I want to check how many processes are running with same names and get their respective counts.

Code:
ps -ef|grep  -Eo 'process1|process2|process3| '|sort -u | awk '{print $2": "$1}'

Output would look like :

Code:
$ ps -ef|grep  -Eo 'process1|process2|process3| '|sort | uniq -c | awk '{print $2": "$1}'
: 108977
process1: 1
process2: 1
process3: 1

It should show 0 values against process1, process 2 and process 3 but it is calculating 1 process for grep command, how to ignore it and get 0.
# 2  
Old 05-31-2017
Does your system have pgrep? If so, does it support the -c, --count option?
Try this:
Code:
#!/bin/bash
for process in "$@"
do
   printf "%s: %d\n" $process $(pgrep -c $process)
done

Andrew
This User Gave Thanks to apmcd47 For This Post:
simpltyansh
# 3  
Old 05-31-2017
Quote:
Originally Posted by apmcd47
Does your system have pgrep? If so, does it support the -c, --count option?
Try this:
Code:
#!/bin/bash
for process in "$@"
do
   printf "%s: %d\n" $process $(pgrep -c $process)
done

Andrew
Unfortunately my system doesn't support pgrep. Smilie
# 4  
Old 05-31-2017
Hi

Did you try | grep -v grep | ?

Code:
ps -ef|grep  -Eo 'process1|process2|process3| '|grep -v grep |sort | uniq -c | awk '{print $2": "$1}'

Last edited by rbatte1; 05-31-2017 at 06:00 AM.. Reason: Changed ICODE tags for CODE tags then wrapped ICODE tags round the in-line code snippet
This User Gave Thanks to radioactive9 For This Post:
simpltyansh
# 5  
Old 05-31-2017
How about
Code:
ps -e -o comm | grep  -Eo 'process1|process2|process3| '|sort | uniq -c

When using ps always use the -o option to specify exactly which fields you need rather than use a full listing and remove the ones you don't.

Andrew
This User Gave Thanks to apmcd47 For This Post:
simpltyansh
# 6  
Old 05-31-2017
With the -E flag that you are already using, the search is for a regular expression. You can include an expression so that grep will not find itself like this:-
Code:
ps -ef | grep -E "Hell[o]"

The [o] matches the single character o which seems illogical until you recognise that the grep process will therefore not match, so it excludes itself.

You have several options separated with pipes so you pick the row if you match any of the items so you will need to do this to each part.


Two more thoughts:-
  • You have a search pattern of a space. Is that really what you want? I would expect much more output if that were true.
  • Your sort -u seems in the wrong place. Perhaps this might be better:-
    Code:
    ps -eo comm= | grep -Eo "whateve[r]|somethin[g]|els[e]" | sort | uniq -c

    I use -o comm= to strip out the headings.

    You do end up with the output the other way round. Is that a problem?


I hope that this helps,
Robin
These 3 Users Gave Thanks to rbatte1 For This Post:
apmcd47 RavinderSingh13 simpltyansh
# 7  
Old 05-31-2017
Quote:
Originally Posted by radioactive9
Hi

Did you try | grep -v grep | ?

Code:
ps -ef|grep  -Eo 'process1|process2|process3| '|grep -v grep |sort | uniq -c | awk '{print $2": "$1}'

Hey Radioactive,
Am sorry, it would give same result as before.
Code:
$ ps -ef|grep  -Eo 'process1|process2|process3| '|grep -v grep |sort | uniq -c | awk '{print $2": "$1}'
: 108766
process1: 1
process2: 1
process3: 1

---------- Post updated at 05:04 AM ---------- Previous update was at 05:02 AM ----------

Quote:
Originally Posted by apmcd47
How about
Code:
ps -e -o comm | grep  -Eo 'process1|process2|process3| '|sort | uniq -c

When using ps always use the -o option to specify exactly which fields you need rather than use a full listing and remove the ones you don't.

Andrew
Thanks Andrew, it was helpful to certain extent. When I run your command, it gives no output, But I was looking for a output like this :

Code:
process1: 0
process2: 0
process3: 0
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