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Adding a timestamp every N row in another column

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# 1  
Old 04-12-2017
Adding a timestamp every N row in another column
Hi,
i have a raw output file like this

Code:
167,63.50

167,63.50

168,63.68

166,63.68

168,63.68

I would like to add every each N rows (for example 60) and in a third column , a timestamp using the command
Code:
date +"%H:%M"

how can i do it with one single command ?

Thank you !!
# 2  
Old 04-12-2017
Hello Board27,

Could you please try following and let me know if this helps you.
Code:
 awk -v DATE=$(date +"%H:%M") -v var=3 'FNR%var==0{print $0,DATE;next} 1'   Input_file

Here in above code I have given value of line as 3 you could change it to as per your need.

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
Board27
# 3  
Old 04-12-2017
it comes :

Code:
314,63.14
 12:22

it is not adding a column with comma. Anyway i express myself in a wrong way. I don't need each N time. I just need to add timestamp at a certain line, for example, if my file has 1000 lines , add a timestemp to the 60th line, 3th column with comma divider.

Thank you anyway for your help!
# 4  
Old 04-12-2017
Hello Board27,

Could you please try following and let me know if this helps you.(Change var's value to your needed line number)
Code:
awk -v DATE=$(date +"%H:%M") -v var=3 'FNR==var{print $0","DATE;next} 1'   Input_file

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
Board27
# 5  
Old 04-12-2017
thanks
# 6  
Old 04-13-2017
Try also
Code:
awk -v DATE=$(date +"%H:%M") -v var=3 'NR==var {$(NF+1) = DATE} 1' OFS=","  file2
167,63.50

167,63.50,22:02

168,63.68

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