Extract number from string.


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# 1  
Extract number from string.

Hi

I am on Sun os. I have data in the below format and I need to grab the number out from the string.

Quote:
Insert completed. 100 rows added
O/p needed:

Quote:
100
---------- Post updated at 12:39 PM ---------- Previous update was at 12:32 PM ----------

I tried this but I am getting . at the front

Quote:
echo "Insert completed. 100 rows added" | tr -d '[:alpha:]'
# 2  
Hello dsravanam,

Could you please try following and let me know if this helps.
Code:
echo "Insert completed. 100 rows added" | awk '{gsub(/[^[0-9]]*/,"");print}'
OR
echo "Insert completed. 100 rows added" | awk '{print $(NF-2)}'
OR
echo "Insert completed. 100 rows added" | awk '{gsub(/[[:alpha:]]|[[:punct:]]| +/,"");print}'

Thanks,
R. Singh
# 3  
Code:
echo 'Insert completed. 100 rows added ' | awk '{print $(NF-2)}'

# 4  
So - punctuation chars and space remain? Where did you get the [:alpha:] character class?
# 5  
works fine with integer :
Code:
$ echo "Insert completed. 100 rows added" | tr -dc '[:digit:]'
100

This User Gave Thanks to Akshay Hegde For This Post:
# 6  
I think none of them are working fine.

Code:
echo "Insert completed. 100 rows added" | tr -dc '[:digit:]'

gives

Code:
Insert completed. rows added

The other one below is not working as it is bringing characters when the string is like below

Code:
echo 'Insert completed. No rows added ' | awk '{print $(NF-2)}'


Code:
No


Last edited by rbatte1; 03-01-2017 at 07:44 AM.. Reason: Changed QUOTE tags to CODE tags
# 7  
Assuming you are using bash...
Longhand, OSX 10.12.3, default bash terminal:-
Code:
Last login: Tue Feb 28 20:19:10 on ttys000
AMIGA:amiga~> ARRAY=( Insert completed. 100 rows added )
AMIGA:amiga~> echo "${ARRAY[2]}"
100
AMIGA:amiga~> _

This assumes that there is always an integer value as the third field.
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