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Returning an exit code from a bash function

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Top Forums Shell Programming and Scripting Returning an exit code from a bash function
# 15  
Old 01-20-2017
Quote:
Originally Posted by RudiC
What if you run ../tut0/load.sh without test? And, how about setting bash's xtrace option?
I didn't know about xtrace. Nice. Thanks for the tip.
Running ../tut0/load.sh directly works fine.
But test.sh is not calling ../tut0/load.sh.

$ cat tests.sh
Code:
#!/bin/bash
echo "in tests.sh --------"
pwd
ls
ls ../tut0

if test ../tut0/load.sh
then
    echo "0"
else
    echo "1"
fi

$ cat ../tut0/load.sh
Code:
#!/bin/bash
echo "in load.sh --------"
pwd
ls
ls ../suite

../suite/main
rc=$?

From the terminal:
Code:
$  bash -x ./tests.sh
+ echo 'in tests.sh --------'
in tests.sh --------
+ pwd
/home/wolfv/Documents/developer/c++/demo/test_script/suite
+ ls
load.sh  load.sh~  main  main.cpp  main.cpp~  tests.sh	tests.sh~
+ ls ../tut0
load.sh  load.sh~
+ test ../tut0/load.sh
+ echo 0
0

I was expecting output to also contain the line "in load.sh --------".
Why is test.sh not calling ../tut0/load.sh?Smilie

Running load.sh directly, pwd prints the directory it was called from, rather than the file's directory:
Code:
$  bash -x ../tut0/load.sh
+ echo 'in load.sh --------'
in load.sh --------
+ pwd
/home/wolfv/Documents/developer/c++/demo/test_script/suite
+ ls
main  main.cpp	main.cpp~  tests.sh  tests.sh~
+ ls ../suite
main  main.cpp	main.cpp~  tests.sh  tests.sh~
+ ../suite/main
in main()-------
+ rc=1
+ echo rc:
rc:
+ echo 1
1
+ exit 1

# 16  
Old 01-20-2017
Remove the test, let if interpret the exit code of load.sh immediately.
# 17  
Old 01-20-2017
Quote:
Originally Posted by RudiC
Remove the test, let if interpret the exit code of load.sh immediately.
That fixed it! Smilie
Thank you RudiC and everyone else that helped along the way.
I could not have done it without you.

The following example works as intended.

$ cat tests.sh:
Code:
#!/bin/bash
echo "in tests.sh --------"
if ../tut0/load.sh
then
    echo "in tests.sh again --------"
    echo "0"
else
    echo "in tests.sh again --------"
    echo "1"
fi

$ cat ../tut0/load.sh:
Code:
#!/bin/bash
echo "in load.sh --------"
../suite/main
rc=$?
echo "rc:"
echo $rc
exit $rc

$ cat main.cpp:
Code:
#include <iostream>

int main()
{
    std::cout << "in main() -------\n";
    return 1; //EXIT_FAILURE
}

From the terminal:
Code:
$  ./tests.sh
in tests.sh --------
in load.sh --------
in main()-------
rc:
1
in tests.sh again --------
1

# 18  
Old 01-23-2017
Quote:
Originally Posted by wolfv
The following example is similar, but with load.sh script in a different directory.
Code:
#!/bin/bash
if test ../tut0/load.sh
then
    echo "0"
else
    echo "1"
fi

You don't evaluate the exit code of load.sh. For example, if you would write

Code:
if test /usr/bin/false
then
  echo yes
fi

you would also get "yes" as answer.

You should write your code as

Code:
if ../tut0/load.sh
then
  echo 0
else
  echo 1
fi
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