cat file02.txt
PATTERN XXX.YYY.ZZZ. 500
ROW01 aaa. 300 XS 14
ROW 45 29 AS XD.FD.
PATTERN 500 ZZYN002
ROW gdf gsste
ALT 267 fhhfe.ddgdg.
PATTERN ERE.MAY. 280
PATTERRNTH 5000 rt.rt.
ROW SO a 678
PATTERN dsjsdh.sdshb 400 80
PATTERN ssds.500. 60
ROW 3389 LAST ROW
I'm trying to join all the lines which start with pattern
Code:
PATTERN
. Also I need to remove the last . if occurs .
The desired results should be:
Code:
XXX.YYY.ZZZ 500 aaa 300 XS 14 45 29 AS XD.FD
500 ZZYN002 gdf gsste 267 fhhfe.ddgdg
ERE.MAY 280 5000 rt.rt SO a 678
dsjsdh.sdshb 400 80
ssds.500 60 3389 LAST ROW
I somehow managed to join the lines but cannot figure out how to get rid of the word PATTERN from output , remove the dot and delete the first word from the lines to be joined.
The spacing in your output is inconsistent and it would have helped if you had explicitly stated that you wanted to remove a trailing period, if present, from each word present in lines being joined; but this seems to come close to what you seem to want:
Code:
awk '
/^PATTERN/ {
if(NR > 1) {
print out
out = ""
}
}
{ for(i = 2; i <= NF; i++)
out = out substr($i, 1, length($i) - ($i ~ /[.]$/)) OFS
}
END { print out
}' file02.txt
As always, if you want to try this on a Solaris/SunOS system, change awk to /usr/xpg4/bin/awk or nawk.
This User Gave Thanks to Don Cragun For This Post:
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