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Partial Match and Replace

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# 1  
Old 12-08-2016
Partial Match and Replace
Hi, I have a tab delimited text file like this one. I need to do a partial match of a particular cell and then replace matches with an empty cell. So here is a sample:

Code:
Smith	FordMustang	ChevroletCamaro
Miller	FordFiesta
Jones	KiaSorrento
Davis	ChevroletCamaro
Johnson	ToyotaHighlander

I need to do a partial match within "makemodel" and replace with noting. For example search "Ford" and replace these partial matching cells with nothing

Code:
Smith		ChevroletCamaro
Miller	
Jones	KiaSorrento
Davis	ChevroletCamaro
Johnson	ToyotaHighlander

Last edited by Don Cragun; 12-09-2016 at 04:06 AM.. Reason: Add CODE tags.
# 2  
Old 12-08-2016
as a start....
Code:
MATCH=Ford
sed -r -e "s/$MATCH[^[:space:]]+//g" file.txt

# 3  
Old 12-08-2016
This works. But on my real dataset, I still have a problem.

The problem is that I need

Code:
sed -E -e "s/ord[^[:space:]]+//g" file.txt

With "ord" to work, too. So it needs to be "wild carded" at the beginning of the word to work, too.

In my "real" dataset, my column has something more like this to be flagged whenever there is Ford

Code:
1998 Ford Mustang
1996 Ford Festiva

---------- Post updated at 07:19 PM ---------- Previous update was at 07:15 PM ----------

And when I use this

Code:
sed -E -e "s/.*ord[^[:space:]]+//g" file.txt

It deletes EVERYTHING before Ford. I only need that particular column cell replaced.
Last edited by Don Cragun; 12-09-2016 at 04:08 AM.. Reason: Add CODE and ICODE tags, again.
# 4  
Old 12-09-2016
Hi,

you can try the following:
Code:
sed -e 's/ Ford[a-zA-z]+//g' file

g is added for global replacement for given input in post #1 g is not required.

or

Code:
awk '{for (i=1;i<=NF;i++) { if ($i ~ /Ford/) $i =x; } }1' file

If it does not help, please post your input and desired output.
# 5  
Old 12-09-2016
Try:
Code:
del=Ford; sed "s/[^[:blank:]]*${del}[^[:blank:]]*//g" infile

or
Code:
awk -v del="Ford" '{for (i=1;i<=NF;i++) if($i~del) $i=x}1' FS='\t' OFS='\t' infile

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