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how to find the field has more than 2 decimals

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# 1  
Old 11-16-2016
how to find the field has more than 2 decimals
Hi Gurus,

I have below sample file, I need find the line which 2rd field has more than 2 decimals.

in sample file, I need to find xyz, 123456.789

Code:
 
 abc, 1234.45, def
xyz, 123456.789, xxx
bce, 1234.34, xxx

thanks in advance
Last edited by ken6503; 11-16-2016 at 10:56 PM.. Reason: subject description is not clear
# 2  
Old 11-16-2016
With well over 100 posts we would have that you have learned something from the suggestions we have provided in helping you with your previous problems. What have you tried to solve this problem on your own?

What shell are you using?

What operating system are you using?
# 3  
Old 11-16-2016
Quote:
Originally Posted by Don Cragun
With well over 100 posts we would have that you have learned something from the suggestions we have provided in helping you with your previous problems. What have you tried to solve this problem on your own?

What shell are you using?

What operating system are you using?
I have tried to search the solution from internet, but no luck at all.

my shell is ksh

my os is solaris.

thanks.
# 4  
Old 11-16-2016
Instead of searching the internet, why don't you look back through all of the solutions you have been given to solve your previous problems and use what you have learned from those solutions to try come up with a very simple nawk script that will do what you have asked for here?
# 5  
Old 11-16-2016
Quote:
Originally Posted by Don Cragun
With well over 100 posts we would have that you have learned something from the suggestions we have provided in helping you with your previous problems. What have you tried to solve this problem on your own?

What shell are you using?

What operating system are you using?
I tried below command but it gave me the record with one decimal as well.

Code:
awk -F"," '$2!~/\.[0-9][0-9]$/ {print $0}' test

# 6  
Old 11-16-2016
Code:
awk -F"," '$2 ~ /\.[0-9][0-9][0-9]/' test

This User Gave Thanks to Aia For This Post:
ken6503
# 7  
Old 11-16-2016
try this...

Code:
awk -F, '{split($2,Arr,".")}length(Arr[2])>2'  test

This User Gave Thanks to itkamaraj For This Post:
ken6503
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