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Use find with cp and sed in ksh to copy files to a slightly different location

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# 1  
Old 10-19-2016
Use find with cp and sed in ksh to copy files to a slightly different location
Hello there wonderful people,

I am running on Solaris 10 and with the following ksh version:
Code:
strings /bin/ksh | grep Version | tail -2
@(#)Version M-11/16/88i

Suppose I want to copy files that end in _v2 from underneath /dir1/dir2/save directory to /dir1/dir2. Basically, what I’m looking for is to remove /save out of the path.

So I was thinking of something like this:
Code:
find /dir1/dir2/save –type f –name *_v2 –exec cp {} `echo {} | sed 's/save//'` \;

But I get this:
Code:
cp: /dir1/dir2/save/app.jar_v2 and /dir1/dir2/save/app.jar_v2 are identical

It looks like putting the output of echo through sed does not work as expected.

Any help is much appreciated.
Thank you!
Last edited by ejianu; 10-19-2016 at 11:23 AM..
# 2  
Old 10-19-2016
The quotes in the sed command look somewhat suspicious...
# 3  
Old 10-19-2016
Not sure why they ended up like that, that is not the issue though. I confirm I use the correct quotes. I will try adding the quotes one more time below to see if they show up correct:
Code:
sed 's/save//'

Yep, above looks better, these are the quotes I use.

Edit: I have also changed the quotes in the original post.
Last edited by ejianu; 10-19-2016 at 11:35 AM..
# 4  
Old 10-19-2016
Hi,

Can you try this one ?
Code:
find /dir1/dir2/save -type f -name *_v2 -exec cp {} `dirname {}` \;

Not tested though.
# 5  
Old 10-19-2016
Quote:
Originally Posted by ejianu
So I was thinking of something like this:
Code:
find /dir1/dir2/save -type f -name *_v2 -exec cp {} `echo {} | sed 's/save//'` \;

There are several problems with this: first, the "{}" placeholder for the found filename can only be used ONCE in a single -exec clause.

Second: you are calling poor sed for every file you find. This is overworking the system.

try the following:

Code:
find /dir1/dir2/save -type f -name "*_v2" -print |\
while read infile ; do
     outfile="${infile%%/save*}${infile*save}"
     print - cp "$infile" "$outfile"
done

I hope this helps.

bakunin
This User Gave Thanks to bakunin For This Post:
ejianu
# 6  
Old 10-19-2016
There might be a # missing - try
Code:
outfile="${infile%%/save*}${infile#*save}"

These 2 Users Gave Thanks to RudiC For This Post:
bakunin ejianu
# 7  
Old 10-19-2016
Quote:
Originally Posted by RudiC
There might be a # missing - try
Code:
outfile="${infile%%/save*}${infile#*save}"

Yes, absolutely. Sorry for the typo and thanks for pointing it out.

bakunin
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