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Modification to awk command

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# 1  
Old 10-18-2016
Modification to awk command
i have a php file that has this:

php.code

Code:
#!/usr/bin/php
<?php 
  phpinfo();
  hlight_file(__FILE__);
?>

I want my awk code grab whatever is inbetween and including the "<?php" and "?>".

Then, it should scan all the entries between these two points. And if the entries between these two points contain the pattern "phpinfo" AND "hlight", i dont want it to output anything.

If it doesn't containing the aforementioned two patterns, then I want it to print everything between and including the "<?php" and "?>".

here's the awk code i'm currently using:

Code:
awk '/phpinfo|hlight/{next}/<?php/,/?>/' php.code

# 2  
Old 10-18-2016
Hello SkySmart,

Let's say we have following Input_file(test one).
Code:
cat Input_file
<?php
  test1
  test2
  phpinfo();
  hlight_file(__FILE__);
?>

Then following code may help in same.
Code:
awk '($0 ~ /^\?>$/){print;A=0} ($0 ~ /^<\?php/){A=1} A && ($0 !~ /phpinfo/) && ($0 !~ /hlight/){print}'   Input_file

Output will be as follows then.
Code:
<?php
  test1
  test2
?>

Thanks,
R. Singh
Last edited by RavinderSingh13; 10-18-2016 at 06:48 AM..
This User Gave Thanks to RavinderSingh13 For This Post:
SkySmart
# 3  
Old 10-18-2016
Quote:
Originally Posted by RavinderSingh13
Hello SkySmart,

Let's say we have following Input_file(test one).
Code:
cat Input_file
<?php
  test1
  test2
  phpinfo();
  hlight_file(__FILE__);
?>

Then following code may help in same.
Code:
awk '($0 ~ /^\?>$/){print;A=0} ($0 ~ /^<\?php/){A=1} A && ($0 !~ /phpinfo/) && ($0 !~ /hlight/){print}'   Input_file

Output will be as follows then.
Code:
<?php
  test1
  test2
?>

Thanks,
R. Singh

if the awk code detects the patterns are present, i want it to avoid printing anything at all. thats what i was unable to do with my original code.
Last edited by SkySmart; 10-18-2016 at 08:02 AM..
# 4  
Old 10-18-2016
Should your system allow for multibyte input and output separators, try
Code:
awk '!(/phpinfo/ && /hlight/)' RS="\?>\n" ORS="?>\n" file

These 2 Users Gave Thanks to RudiC For This Post:
looney SkySmart
# 5  
Old 10-18-2016
RudiC solution is great. Smilie

In sed :

Code:
sed -re '/^<\?php/,/\?>/{N;N;N;/.*phpinfo.*\n.*hlight_file.*\n?>/d}'  file

Code:
cat file
#!/usr/bin/php
<?php
  phpinfo();
  hlight_file(__FILE__);
?>
<?php
how
  hlight_file(__FILE__);
?>
<?php
  phpinfo();
  hlight_file(__FILE__);
?>
<?php
target
src
?>

Gives output:
Code:
#!/usr/bin/php
<?php
how
  hlight_file(__FILE__);
?>
<?php
target
src
?>

This User Gave Thanks to greet_sed For This Post:
SkySmart
# 6  
Old 10-18-2016
Code:
awk '
/<[?]php/ {b=1; php=""; php=php $0 RS; next}
! b ; b {php=php $0 RS}
/[?]>/ {if (php ~ /phpinfo/ && php ~ /hlight/) {php=""} else {printf php}; php=""; b=0}
' infile

# 7  
Old 10-18-2016
Quote:
Originally Posted by greet_sed
.
.
.
In sed :

Code:
sed -re '/^<\?php/,/\?>/{N;N;N;/.*phpinfo.*\n.*hlight_file.*\n?>/d}'  file

.
.
.
This works well on the sample given. But, the specification doesn't say that
- the two patterns follow in the next TWO consecutive lines
- the order of the patterns is given

Should the be more lines to the records, and should the patterns be reversed, try

Code:
sed -re '/^<\?php/ {:L; N; /\?>/!bL; /(phpinfo.*hlight)|(hlight.*phpinfo)/d}'  file

It reads the entire record no matter how long it is, and then deletes it should both patterns show up in no matter what sequence.
Last edited by RudiC; 10-18-2016 at 11:06 AM..
These 2 Users Gave Thanks to RudiC For This Post:
greet_sed SkySmart
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