Shell Programming and Scripting

Hi Rudi,

Thanks for the reply.
Yes you are right. it should be line.

Thanks
Bharat

Try

Code:

sed -e 1n -e '$n' -e '/^.\{179\}I/ !s/./I&/180' file

Thank you. I will try this and update you.

Thanks
Bharat

---------- Post updated at 12:05 PM ---------- Previous update was at 11:37 AM ----------

It works. Just fine. Thanks a lot.

Code:

for file in *.RET
do
echo "File Name in PROCESS Stage=" $file

#Insert character 'I' at 180th position if this chracter not exist
#sed -e 1n -e '$n' -e 's/./I&/180' "$file" > "$tmpf" && cp "$tmpf" "$file"
sed -e 1n -e '$n' -e '/^.\{179\}I/ !s/./I&/180' "$file" > "$tmpf" && cp "$tmpf" "$file"

done

With any POSIX-conforming sed you could also use:

Code:

sed -e 1n -e '$n' -e 's/^\(.\{179\}\)\([^I]\)/\1I\2/' "$file" > "$tmpf" && cp "$tmpf" "$file"

but RudiC's suggestion may be easier for some people to read.

Hi Team,

My requirement is slightly changed and please help on the below.

Earlier i was trying insert a character(I) at 180th position of all the lines in the file except 1st and last line. Now i have little change in this requirement, I just need to replace whatever character in 180 the position to chracter "I".

I was using below code, But i am trying different options buts its not working.

Code:

sed -e 1n -e '$n' -e '/^.\{179\}I/ !s/./I&/180' "$file" > "$tmpf" && cp "$tmpf" "$file"

what code if i change in the above line,so i can make this work?

Thanks
Bharat

---------- Post updated at 10:59 AM ---------- Previous update was at 10:34 AM ----------

Hi Team,

I tried below code and it looks working fine. Please suggest of there any better way of doing it.

Code:

sed -e 1n -e '$n' -e 's/./I/180' "$file" > "$tmpf" && cp "$tmpf" "$file"

Many thanks.

Thanks
Bharat

Hi,

IMO, command you have tried looks good