Remove trailing empty spaces within a quote


 
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# 1  
Old 10-05-2016
Remove trailing empty spaces within a quote

Platform: Oracle Linux 6.5
I have a file with hundreds of values enclosed in single quotes like below. I want the trailing empty spaces before the ending quote to be removed. Expected output shown below. Can this be done using good old vi editor ? Or should I use sed or awk for this ?

Code:
$ cat someStings.txt
'ABC  '
'CDE  '
'FGHIJKL  '
'MN  '

Expected output:

Code:
'ABC'
'CDE'
'FGHIJKL'
'MN'

Note : unix.com's editor is not working well with my Firefox or Chrome browser. Because of this , I see a preceeding space before 'ABC' in the 'Exprected output' . Please ignore this.

Last edited by zaxxon; 10-05-2016 at 05:58 AM.. Reason: removed the preceding spaces
# 2  
Old 10-05-2016
For your special case given above, try
Code:
awk '{sub (/ *\047$/, "\047")} 1' file

It doesn't account for leading space/quote combinations nor for those not at line end.
This User Gave Thanks to RudiC For This Post:
# 3  
Old 10-05-2016
Code:
$ cat test.txt
'ABC  '
'CDE  '
'FGHIJKL  '
'MN  '
'TEST HELLO   '
' HI TEST TXT   '


$ sed "s, *'$,',g" test.txt
'ABC'
'CDE'
'FGHIJKL'
'MN'
'TEST HELLO'
' HI TEST TXT'

These 2 Users Gave Thanks to itkamaraj For This Post:
# 4  
Old 10-05-2016
Hello kraljic,

Following may also help you in same too.
Code:
perl -p -e "s/ *'/'/g"   Input_file

Output will be as follows.
Code:
'ABC'
'CDE'
'FGHIJKL'
'MN'

Thanks,
R. Singh
# 5  
Old 10-05-2016
Hi kraljic,
As to your question of whether or not this can be done "using good old vi editor", the answer is yes. The command:
Code:
:g/  *'$/s//'/

will do it. And, of course, this also means that if you're using the good old ed or ex editors, you can also accomplish the same thing with the command:
Code:
g/  *'$/s//'/

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