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awk with passing variable

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# 8  
Old 08-17-2016
You could also try:
Code:
sed -n "/$start/,/$end/p" file

But, note that all of the suggestions that have been given will also print all lines from a line that matches $start to the end of the file if no line after that matches the RE specified by $end. Your problem statement doesn't say what should happen in this case.
# 9  
Old 08-17-2016
Thank you. I need to print all lines that matches start to end.

---------- Post updated at 09:23 PM ---------- Previous update was at 09:22 PM ----------

Quote:
Originally Posted by RavinderSingh13
Hello mychbears,

Could you please try following and let me know if this helps you.
Code:
awk -v v_start="$start" -v v_end="$end" '$0~v_start{flag=1;}$0~v_end{print;flag=0}flag'  Input_file
OR
awk -v v_start="$start" -v v_end="$end" '$0~v_start{flag=1;print;next}$0~v_end{print;flag=0}flag'  Input_file
OR
awk -v v_start="$start" -v v_end="$end" '$0~v_start{flag=1;};flag;$0~v_end{flag=0}'  Input_file

Output will be as follows in above all 3 solutions.
Code:
one
two
three
four
five
ten

Thanks,
R. Singh
---------- Post updated at 09:23 PM ---------- Previous update was at 09:23 PM ----------

Thank you Singh. It worked great.

---------- Post updated at 09:24 PM ---------- Previous update was at 09:23 PM ----------

Quote:
Originally Posted by RudiC
Try also
Code:
awk -vST=$start -vEN=$end '$0~ST, $0~EN' file
one
two
three
four
five
ten

---------- Post updated at 09:25 PM ---------- Previous update was at 09:24 PM ----------

It worked great. Thank you all for your suggestions.
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