Grouping and counting


 
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# 1  
Old 08-15-2016
Grouping and counting

Hello,

I would like to group/sort a file of records by a particular field and then count how many records belong in that grouping.

For example say I have the following data:

Code:
1234|"ZZZ"|"Date"|"1"|"Y"|"ABC"|""|AA
ABCD|"ZZZ"|"Date"|"1"|"Y"|"ABC"|""|AA
EFGH|"ZZZ"|"Date"|"1"|"Y"|"ABC"|""|BB
IJKLM|"ZZZ"|"Date"|"1"|"Y"|"ABC"|""|BB
NOPQ|"ZZZ"|"Date"|"1"|"Y"|"ABC"|""|BB

i.e. I'd like to group by the last field and count so effectively the output would look as so:

Code:
AA 2
BB 3

etc...
# 2  
Old 08-15-2016
Try awk:
Code:
awk -F '|' {arr[$(NF)]++} END {for(i in arr) {i, arr[i]}} ' inputfile

Data will not come out sorted, you can pipe the result into sort if you need it that way.
This User Gave Thanks to jim mcnamara For This Post:
# 3  
Old 08-15-2016
Hello Nik44,

Welcome to forums, hope you will enjoy learning knowledge here. Could you please try following and let me know if this helps(if you are not bothered about sequence of output).
Code:
awk -F"|" '{A[$NF]++} END{for(i in A){print i, A[i]}}'  Input_file

Output will be as follows.
Code:
BB 3
AA 2

If you need output in same sequence as Input_file then try as follows(By reading Input_file 2 times in following solution).
Code:
awk -F"|" 'FNR==NR{A[$NF]++;next} ($NF in A){print $NF, A[$NF];delete A[$NF]}'   Input_file  Input_file

Output will be as follows.
Code:
AA 2
BB 3

Hope this helps you.

Thanks,
R. Singh

Last edited by RavinderSingh13; 08-15-2016 at 09:41 AM..
# 4  
Old 08-15-2016
Hi.

Also with standard utilities:
Code:
cut -f8 -d'|' <your-input-file> | sort | uniq -c

producing
Code:
      2 AA
      3 BB

Best wishes ... cheers, drl
This User Gave Thanks to drl For This Post:
# 5  
Old 08-15-2016
Thanks for the reponses! I've gone for the more straight forward cut option as it provides the desired output.

However I forgot to add to this question... Is there a way of refining this output further so that it will only count a record of that group where field four is "1" and where field five is "Y"? I realise in the example supplied it would still show the exact same count.
# 6  
Old 08-15-2016
Quote:
Originally Posted by Nik44
Thanks for the reponses! I've gone for the more straight forward cut option as it provides the desired output.
However I forgot to add to this question... Is there a way of refining this output further so that it will only count a record of that group where field four is "1" and where field five is "Y"? I realise in the example supplied it would still show the exact same count.
Hello Nik44,

Could you please try following and let me know if this helps you.
Code:
awk -F"|" 'FNR==NR{gsub(/\"/,X,$0);if($4==1 && $5=="Y"){A[$NF]++};next} ($NF in A){print $NF, A[$NF];delete A[$NF]}'  Input_file  Input_file

On a Solaris/SunOS system, change awk to /usr/xpg4/bin/awk, /usr/xpg6/bin/awk , or nawk.

Thanks,
R. Singh
# 7  
Old 08-15-2016
Thanks Ravinder.

The command executes without any issues, however doesn't seem to have altered the file (is identical as to pre the command). Is this perhaps because my data includes literal double quotes?

I tried escaping them but doesn't seem to make any difference Smilie
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