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Shell Programming and Scripting

Get remaining line after string match

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# 1  
Old 06-28-2016
Get remaining line after string match
Want to get the remaining line after pattern match
Code:
 Here it starts - executed commands : - pattern to identify 100:27:500:1:34:END

Required output:
Code:
100:27:500:1:34:END

Code:
awk '{if(/pattern to identify/) print $2}' < file

I have used above code and it not giving required output, can anyone provide solution to get the required output?
# 2  
Old 06-28-2016
Code:
echo 'Here it starts - executed commands : - pattern to identify 100:27:500:1:34:END' | awk 'match($0, "pattern to identify") {print substr($0,RSTART+RLENGTH+1)}'

# 3  
Old 06-29-2016
Code:
perl -nle '/pattern to identify\s+(.*)/ and print $1' rozee.file

# 4  
Old 06-29-2016
Try also
Code:
echo 'Here it starts - executed commands : - pattern to identify 100:27:500:1:34:END' | awk 'sub ("^.*pattern to identify ", "")'
100:27:500:1:34:END

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