Need code for updating second record to first record in shell scripting


 
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# 1  
Old 06-28-2016
Need code for updating second record to first record in shell scripting

Hi,,

I have requirement that i need to get DISTINCT values from a table and if there are two records i need to update it to one record and then need to submit INSERT statements by using the updated value as a parameter. Here is the example follows..

Code:
SELECT DISTINCT ID FROM OFFER_GROUP WHERE OFFERS IN('A','B');

Result as follows
Code:
ID
1
11

Above statement always displays 1 or 2 records.If the above query returns 2 rows then i need to update it to 1 row like below

Code:
UPDATE OFFER_GROUP SET ID =1 WHERE OFFERS IN('A','B') AND ID =11;

And then i need to execute INSERT statements by using ID as a parameter.
whenever i use ${ID} it should be place with the updated value 1.

insert into <TABLE>values ();

For the above requirement, i need to implement it in shell scripting and i am using nzsql.

Thanks in advance.

Cheers,
Samah

Last edited by Don Cragun; 06-28-2016 at 09:13 PM.. Reason: Fix CODE tags inside CODE tags.
# 2  
Old 06-29-2016
Please help me out on this above requirement
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