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How to pick system time of the file placed on UNIX?

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Top Forums Shell Programming and Scripting How to pick system time of the file placed on UNIX?
# 15  
Old 06-09-2016
That never fell into place...
# 16  
Old 07-01-2016
Hi All,

I want some help once again. I tried many commands for picking the system timestamp for a particular file.
by
Code:
ls -l

, i am only getting date and time but not year, so this command is not fulfilling my requirement
Code:
ls -l 79396246719284800001_WBR_REPORT_PROCESS_STATUS_1467192848.mdata | awk '{print $6,$7,$8}'
Jun 29 09:43

I want the date with current year also and final out put is required in following format
Code:
29/06/2016 09:43:00

.
Stat is not working in unix .I tried istat ,it gives me very elaborated output , through which I grep only last modified line and found below output :-
Code:
istat file.ksh |grep "Last modified:"
Last modified:  Fri Jul  1 06:31:43 GMT 2016

Please help in converting to dd/mm/yyyy hh24:mi:ss

Regards
Ruchika
# 17  
Old 07-01-2016
Did you realise Corona688's post#14?
# 18  
Old 07-01-2016
Yes RudiC , i went through Corona688's post#14 but
Code:
date -r

and
Code:
date -d

doesn't work for me.
Code:
date -r WBR_REPORT_PROCESS.log +"%y/%m/%d %H:%M:%S"
date: Not a recognized flag: r
Usage: date [-u] [+"Field Descriptors"]

I have never used Perl. But can try if you can provide me any specific command.

Regards
Ruchika
# 19  
Old 07-01-2016
There's a link in post#14...?
# 20  
Old 07-01-2016
Thanks for all your help..I am done with everything else..one last help required is with sed command. When i am using this command in shell script
I used a variable vfile2 to define some value
Code:
            v_File2=`echo ${NPI_DIRECTORY}/$file_name | cut -d'_' -f1`

when I try to print in my logs, i am getting the value of this variable correctly.
But when I try to use it in sed command then it appends ${v_File2} in the file,instead of its value.

Code:
`sed -e 's/$/   ${v_File2}/' ${NPI_DIRECTORY}/$file_name > ${NPI_DIRECTORY}/${file_name}_temp`

I tried it in many styles ( ${v_File2}, "${v_File2}", $v_File2,%${v_File2}) but nothing worked .

File after sed command :-

Code:
FILE_NAME       REPORT_ID       REPORT_NAME     REPORT_NAME1       ID1   ID2 REPORT_CATEGORY CATEGORY    REGION  CREATION_TIMESTAMP     TIMESTAMP        ${v_File2}

Regards
Ruchika
# 21  
Old 07-01-2016
Single quotes suppress shell's expansion. Use double quotes for this special case. And, you should prefer the $(...) construct to backticks `...` for "command substitution".
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