How to pick system time of the file placed on UNIX?


 
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Top Forums Shell Programming and Scripting How to pick system time of the file placed on UNIX?
# 8  
Old 06-08-2016
Not sure what do you mean by
Code:
 stat

equivalent. We use
Code:
ls-l

or
Code:
ls-ltr

to check timestamp. Hope it helps.
# 9  
Old 06-08-2016
Code:
stat -c"%y" file
2016-03-14 11:58:07.955460988 +0100

can yield single details from the file system directly.
# 10  
Old 06-08-2016
stat command does not work for me in ksh shell.

Tried using this instead :-
Code:
ls -l Data_file.sql | awk '{print $6,$7,$8}'
Jun 08 05:56

Any idea if I can convert this out put to following format
Code:
08/06/2016 05:56:50

Any help would be appreciated
# 11  
Old 06-08-2016
The locale definition might help...
# 12  
Old 06-08-2016
Quote:
Originally Posted by Ruchika
stat command does not work for me in ksh shell.
Tried using this instead :-
Code:
ls -l Data_file.sql | awk '{print $6,$7,$8}'
Jun 08 05:56

Any idea if I can convert this out put to following format
Code:
08/06/2016 05:56:50

Any help would be appreciated
Hello Ruchika,

If you have GNU version of ls command then following may help you in same.
Code:
ls -l Input_file --time-style="+%d/%m/%Y  %H:%M:%S" | awk '{print $(NF-2) OFS $(NF-1)}'

Thanks,
R. Singh
# 13  
Old 06-09-2016
GNU date available? Try
Code:
DT=$(date -d "$(LC_ALL=C ls -l summary_file.sql | awk '{print $6,$7,$8}')" +"%y/%m/%d %H:%M:%S")
sed -e "s/$/   $DT/" summary_file.sql > Data_file.sql

# 14  
Old 06-09-2016
GNU date can be used more simply than that with its -r reference file option:

Code:
DT=$(date -r summary_file.sql +"%y/%m/%d %H:%M:%S")

GNU date might be available on some Solaris as gdate or /usr/bin/gnu/date.

If you don't have GNU date, but do have Perl, you could try my GNU date stand-in which also supports -r.
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