Help with Getting distinct record count from a .dat file using UNIX command


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# 1  
Help with Getting distinct record count from a .dat file using UNIX command

Hi,
I have a .dat file with contents like the below:

Input file

Code:
 ============SEQ NO-1: COLUMN1==========
 9835619
 7152815
============SEQ NO-2: COLUMN2 ==========
  7615348
 7015548
  9373086
============SEQ NO-3: COLUMN3===========
 9373086


Expected Output: (I just need the total distinct count of records under a separate header-as like below)
Code:
 ============SEQ NO-1: COLUMN1==========
2
============SEQ NO-2: COLUMN2 ==========
 3
 ============SEQ NO-3: COLUMN3===========
1

Please help me with the unix command for the same.

Last edited by Don Cragun; 06-07-2016 at 05:04 AM.. Reason: Add CODE tags.
# 2  
Hello MS06,

Welcome to forums, request you to please use code tags as per forum rules for commands/codes/Inputs which you are using into your posts. For your requirement, could you please try following.
Code:
awk '/^==/{if(count){print count;count=""};print;next} {count++} END{print count}'   Input_file 
OR
awk '/^==/{if(count){print count;count=""};print;next} !/^$/{count++} END{print count}'  Input_file

Second solution will leave all empty lines and will not count them. So output will be as follows.
Code:
============SEQ NO-1: COLUMN1==========
2
============SEQ NO-2: COLUMN2 ==========
3
============SEQ NO-3: COLUMN3===========
1

Thanks,
R. Singh
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