1st scenario:
if the fourth column contains 888s and 0s it is by DEPT and "DEPT" will appended into the end of file.
here's what i did and got successfully condition
for i in `ls *.txt`; do
ONE=${i}
flag="1"
while read line
do
DEPT=`echo $line | awk -F "," '{print $3}'`
SDEPT=`echo $line | awk -F "," '{print $4}'`
if [ "$SDEPT" == 888 ] || [ "$SDEPT" == 0 ]; then
flag="1"
else
flag="0"
break
fi
done <$i
if [ $flag == "1" ]
then
TWO="Area_by_DEPT"
else
TWO="Area_by_CLASS"
fi
uploadfile=`echo ${ONE} | awk -F'.' '{print $1}'`
sed -i -e "s/^/$DT_NOW_YYYYMMDD,${uploadfile},${TWO},/" ${ONE}
mv ${ONE} ${ONE}_${TWO}
done
My output is: file1.txt_Area_by_DEPT
i got the correct output.
2nd scenario:(including the 1st condition)
if the fourth column does not contains 888s and 0s it is by CLASS and "CLASS" will appended into the end of file.
here's what i've done.
for i in `ls *.txt`; do
ONE=${i}
flag="1"
while read line
do
DEPT=`echo $line | awk -F "," '{print $3}'`
SDEPT=`echo $line | awk -F "," '{print $4}'`
if [ "$SDEPT" != 888 ] || [ "$SDEPT" != 0 ]; then
flag="1"
else
flag="0"
break
fi
done <$i
if [ $flag == "1" ]
then
TWO="Area_by_DEPT"
else
TWO="Area_by_CLASS"
fi
uploadfile=`echo ${ONE} | awk -F'.' '{print $1}'`
sed -i -e "s/^/$DT_NOW_YYYYMMDD,${uploadfile},${TWO},/" ${ONE}
mv ${ONE} ${ONE}_${TWO}
done
My output: file1.txt_Area_by_CLASS
i got the successfull output because of the else statement
(else
flag="0"
break
fi
0
3rd scenario: the condition 1, 2 will be included on this 3rd condition. here i'm stuck i don't know what to do.
if the 3rd column
contains 55, 16, 76 and the fourth column is equal to 888 and 0 it's by CLASS and "CLASS" will appended into the end of file.
Expected output will be file1.txt_Area_by_CLASS
Code:
Summary Condition:
if the 4th column = 888 or 0 then it's by DEPT
if the 4th column not equal 888 or 0 then it's by CLASS
if the 3rd column contains 55, 16, 76 and 4th column = 888 or 0 then it's the same as by CLASS
if the 3rd column contains 55, 16, 76 and 4th column not equal 888 or 0 then it's the same as by CLASS
Hope you understand.
Need your expertise guys.
Please advise,
Last edited by znesotomayor; 05-05-2016 at 10:56 PM..
Reason: rephrase
I'm stuck on how to put all that condition. all my testing is wrong. my output is always file1.class although the 4th column is only 888 and 0. it's contradictory
Please take a step back and rephrase the logics/conditions. And, an input sample containing ALL cases plus an indication what should go where might be of invaluable help - for you as well.
Apologies Sir Rudic. How do i run it on if statement? i'm encountering command not found.
Code:
#!/bin/sh
for i in `ls *.txt`; do
while read line
do
DEPT=`echo $line | awk -F "," '{print $3}'`
SDEPT=`echo $line | awk -F "," '{print $4}'`
if ($SDEPT == 888 || $SDEPT == 0) && !($DEPT == 55 || $DEPT == 16 || $DEPT == 76); then
echo dept
else
class
fi
done <$i
done
Code:
output
test.sh: line 8: 888: command not found
test.sh: line 8: 888: command not found
test.sh: line 11: class: command not found
test.sh: line 8: 0: command not found
test.sh: line 8: 0: command not found
test.sh: line 11: class: command not found
test.sh: line 8: 888: command not found
test.sh: line 8: 888: command not found
test.sh: line 11: class: command not found
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