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Shell Programming and Scripting

Find words containing small letters

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# 1  
Old 04-10-2016
Find words containing small letters
Hello, I have a file containing different words. How can i print the words which contain at least one small letter, for example if i have:

Code:
today TOMORROw 12345 123a
next preViou5 no

it should print the following:

Code:
today TOMORROw 123a
next preViou5 no

Moderator's Comments:
Mod Comment Please use code tags as required by forum rules!
Last edited by RudiC; 04-10-2016 at 02:16 PM.. Reason: Added code tags
# 2  
Old 04-10-2016
Any attempts/ideas/thoughts from your side?
# 3  
Old 04-10-2016
Code:
for word in $(<$f1); do
        echo $word | grep "[a-z]"
done

$f1 stores the file name, the problem with my code is that the words are printed on separated lines.
# 4  
Old 04-10-2016
Please post your OS and shell next time.

On some OS, echo -n suppresses <new line> chars. Or, use printf if available in your system or shell.

This is a quick awk solution:
Code:
awk '{for (i=1; i<=NF; i++) if ($i !~ /[a-z]/) $i = ""} 1' file3
today TOMORROw  123a
next preViou5 no

if you can tolerate the two spaces where a field has disappeared.
# 5  
Old 04-10-2016
Thank you, problem solved!
# 6  
Old 04-10-2016
Quote:
Originally Posted by JhonTheNewbie
Code:
for word in $(<$f1); do
        echo $word | grep "[a-z]"
done

$f1 stores the file name, the problem with my code is that the words are printed on separated lines.
Hi, I think your code is cool but a little tricky,could you explain the meaning of this "$(<$f1)" especially the "<" here,thank you!
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