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Change Date Input :-

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Top Forums Shell Programming and Scripting Change Date Input :-
# 8  
Old 04-06-2016
in your script change #!/bin/ksh to #!/bin/ksh93
# 9  
Old 04-06-2016
Command not Found

Code:
./test.sh

# 10  
Old 04-06-2016
Quote:
Originally Posted by asavaliya
Command not Found

Code:
./test.sh

must be in a diff path - probably /usr/bin/ksh93 - don't have Solaris in front of me.
Try it with /usr/bin/bash...

What Solaris version are you on? Do uname -a
This User Gave Thanks to vgersh99 For This Post:
asavaliya
# 11  
Old 04-06-2016
Now its Working

Thanks Guys
# 12  
Old 04-06-2016
IMO it'd be better to perform such calculations in perl as it has the built in libraries for handling date/time requirements...
# 13  
Old 04-09-2016
ksh93 using builtin time conversion and calculation:
Code:
#!/usr/bin/ksh93

X1=02 ### Hour
Y1=20160405 ## Date
Z1=4 ## I want to Back 4 Hour

day=$(printf "%(%Y-%m-%d)T" $Y1)
timestamp="$day $X1:00:00"
epoc=$(printf "%(%#)T" "$timestamp")


cnt=1
str=""
while ((cnt<=Z1))
do

        h=$(printf "%(%H)T" "#$epoc")
        ((h==0)) && h=24
        str="$str$h "
        ((epoc-=3600))  # 1 hour, 3600 s
        ((cnt+=1))
done

endday=$(printf "%(%Y%m%d)T" "#$epoc")
echo List=$str
echo Y1=$endday

# 14  
Old 04-10-2016
Hi.

I agree with shamrock, and there is a perl version of date right here: https://www.unix.com/tips-tutorials/2...te-script.html -- I call it date.pl on my system.

Here's a demo snippet:
Code:
pl " Standard date:"
/usr/bin/date

pl " Standard date with arithmetic correction of -15 hours (expect fail):"
/usr/bin/date --date="15 hours ago"

pl " Standard date with arithmetic correction of -15 hours (expect fail):"
/usr/xpg4/bin/date --date="15 hours ago"

pl " perl version of date:"
date.pl --date="-15 hours"

producing:
Code:
 Standard date:
Sun Apr 10 03:25:53 CDT 2016

-----
 Standard date with arithmetic correction of -15 hours (expect fail):
/usr/bin/date: illegal option -- date=15 hours ago
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]

-----
 Standard date with arithmetic correction of -15 hours (expect fail):
/usr/xpg4/bin/date: illegal option -- date=15 hours ago
usage:  date [-u] mmddHHMM[[cc]yy][.SS]
        date [-u] [+format]
        date -a [-]sss[.fff]

-----
 perl version of date:
2016-04-09 12:25:54

For a sysem like:
Code:
Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: SunOS, 5.11, i86pc
Distribution        : Oracle Solaris 11.3 X86
bash GNU bash 4.1.17
date - ( /usr/bin/date, 2016-04-10 )
date.pl - ( local: RepRev 1.4, ~/bin/date.pl, 2014-02-18 )

Bedst wishes ... cheers, drl
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