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awk to print before and after lines then count of patterns

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# 1  
Old 03-30-2016
awk to print before and after lines then count of patterns

What i'm trying to do here is show X amount of lines before and after the string "serialNumber" is found.

gawk '{a[NR]=$0} {count=0} /serialNumber/ && /./ {for(i=NR-'"${BEFORE}"';i<=NR;i++){count++ ;print a[i]}for(i=1;i<'"${AFTER}"';i++){getline; print ; count ++; print count}exit}' datafile

it's not outputting correctly.

the goal here is to have the awk command do the following:

1. show the 3 lines that come BEFORE 'serialNumber'
2. show the actual line containing 'serialNumber'
3. show the 2 lines that come AFTER 'serialNumber'
4. show the count of lines found containing 'serialNumber'

if more than one line is found containing 'serialNumber', only steps 1 through 3 should be performed on each line found.

then at the very end of the output, there should be the total number of lines containing 'serialNumber'.

i know its complicated. can this be done?
# 2  
Old 03-30-2016
Deleted. More concise script provided by Chubler_XL on this thread.

Last edited by rdrtx1; 03-31-2016 at 12:39 AM.. Reason: updated for req. 4 (count in block of lines)
This User Gave Thanks to rdrtx1 For This Post:
# 3  
Old 03-30-2016
Can you post a sample of the input file...
# 4  
Old 03-30-2016
We could simplify rdrtx1's the code to:

awk '
/serialNumber/ {c++; t++; for(i=NR-3; i<=NR+2; i++) o[i]=c; next}
   for(i=1; i<=NR; i++) {
       if (o[i]) print l[i];
       if (o[i]>1 && !(o[i+1]))
            print "cnt: " o[i];
   print "total count: " t+0;
' infile

# 5  
Old 03-31-2016
Never mind then.

Last edited by rdrtx1; 03-31-2016 at 12:38 AM..
# 6  
Old 03-31-2016
Some further testing has highlighted issues when display regions overlap e.g.:

4 serialNumber
13 serialNumber
14 serialNumber
17 serialNumber
18 serialNumber
19 serialNumber
20 serialNumber

This updated code should display correct "cnt: " subtotals: and uses variables BEFORE and AFTER

awk -v BEFORE=3 -v AFTER=2 '
/serialNumber/ {
   for(i=NR-BEFORE; i<=NR+AFTER; i++)
      if(i>NR||!o[i]) o[i]=c
   for(i=1; i<=NR; i++) {
       if (o[i]) {
           print l[i]
           if (i==NR||o[i+1]<o[i])
            print "cnt: " o[i]
   print "total count: " t+0
}' infile

Last edited by Chubler_XL; 03-31-2016 at 01:48 AM..

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