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3digit block separated by a dot and a hyphen

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# 1  
Old 03-19-2016
3digit block separated by a dot and a hyphen
once again I need a hint how to operate a dot and a hyphen.
my aim is to use

Code:
echo $RANDOM$RANDOM$RANDOM

giving me a bunge of numbers. I need to seperate them into yyy.xxx.zzz-tt

Code:
sed i\.

makes a dot in front of the output. Before that I tried something like
Code:
jot -r -n 8 0 9 | rs -q 0

or even more daring the apg-command
and last but not least working out an array e.g.(this is just an example how it could be done)
Code:
array=(This is a text)
               echo ${array [0]:2:2}

ANY HINTS ? Thanks in advance!
Last edited by 1in10; 03-19-2016 at 07:39 PM.. Reason: solved
# 2  
Old 03-19-2016
What's wrong with
Code:
echo $RANDOM.$RANDOM.$RANDOM
31533.27416.10085

?
This User Gave Thanks to RudiC For This Post:
1in10
# 3  
Old 03-19-2016
Would that work?
Code:
printf "%.3s.%.3s.%.3s-%.2s\n" $RANDOM, $RANDOM, $RANDOM, $RANDOM
141.470.200-20

This User Gave Thanks to Aia For This Post:
1in10
# 4  
Old 03-19-2016
Quote:
Originally Posted by Aia
Would that work?
Code:
printf "%.3s.%.3s.%.3s-%.2s\n" $RANDOM, $RANDOM, $RANDOM, $RANDOM
141.470.200-20

This runs a risk of having some one and two digit numbers followed by a comma in cases where $RANDOM expands to a value less than 100. For instance, sticking your command in a while loop for a couple of seconds and grepping the output for commas produce a couple of dozen lines of output including:
Code:
127.258.34,-2,

But, that problem can easily be fixed using the same logic with something like:
Code:
printf '%03d.%03d.%03d-%02d\n' $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%100))

which luckily produced the output:
Code:
065.154.834-83

the first time I tried it (note the leading zero).
This User Gave Thanks to Don Cragun For This Post:
1in10
# 5  
Old 03-19-2016
Hi.

If a conveniently-specified range is useful:
Code:
$ printf "%.3s.%.3s.%.3s-%.2s\n" $(shuf -i 1-255 -n 3) $(shuf -i 0-59 -n 1)

Resulting in, for example:
Code:
54.152.170-4

On a system like:
Code:
OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution        : Debian 8.3 (jessie) 
shuf (GNU coreutils) 8.23

Best wishes ... cheers, drl
This User Gave Thanks to drl For This Post:
1in10
# 6  
Old 03-22-2016
the final result that works on linux is, at least for me, the following one:
Code:
printf "%03d.%03d.%03d.-%02d\n" $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%100))

thanks to all, I appreciate it!!!
# 7  
Old 03-22-2016
Quote:
Originally Posted by 1in10
the final result that works on linux is, at least for me, the following one:
Code:
printf "%03d.%03d.%03d.-%02d\n" $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%100))

thanks to all, I appreciate it!!!
That won't get the output format you said you wanted. You have an extra period in your format string. I think you want:
Code:
printf "%03d.%03d.%03d-%02d\n" $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%100))

instead of:
Code:
printf "%03d.%03d.%03d.-%02d\n" $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%1000)) $((RANDOM%100))
----------------------^

This User Gave Thanks to Don Cragun For This Post:
1in10
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