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Script to monitor diskspace of /home/ not to exceed 80%

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# 1  
Old 03-14-2016
Hammer & Screwdriver Script to monitor diskspace of /home/ not to exceed 80%
I want to monitor the diskspace of the /home/ directory NOT to exceed 80%.
I want a script_file.sh for this.

I am trying "df -h" command and I am stuck unable to extract the percentage.

1. HOW TO extract the percentage (I believe 5th column)?

2. IF we were able to extract the column, will it return just the value or the value with "%" sign?

3. I want this value to be tested in a IF condition to check its >80%

Please help me quick, its urgent!!
Thanks Smilie
# 2  
Old 03-14-2016
You better use df -kP or df -k in a script.
The % in bash/ksh/ash/psh can be chopped off.
Code:
percent=`df -kP /home/. | awk 'NR>1 {print $5}'`
percent=${percent%*%}

or
Code:
percent=`df -kP /home/. | (read _; read _ _ _ _ percent _; echo  ${percent%*%})`

This User Gave Thanks to MadeInGermany For This Post:
Shreyas N
# 3  
Old 03-14-2016
thanks, but what does NR>1 do? and what is ${percenta%*%}

does it return only one value of the entire /home/ directory ? coz I need that.

will
Code:
IF [ $( df -kP /home | awk '{print $5}' ) -gt 80]; then
                  echo "exceeds"
               else
                   echo "don't"
               FI

this work?
# 4  
Old 03-14-2016
NR > 1 skips the first (= header) line in awk. shell's parameter expansion ${percent%*%} (no "a"!) removes the trailing % sign.

It will not, due to syntactical and semantical errors:
- IF should be lower case
- the closing ] needs a leading space
- the command substitution needs double quotes
- the test ( or [ ) command can't handle multiline arguments, it needs a single item output from the command substitution.
- the -gt comparison can't handle the % sign
This User Gave Thanks to RudiC For This Post:
Shreyas N
# 5  
Old 03-14-2016
${percent%*%} is a variable modifier. So you must store it in a variable first.
Code:
percent=`df -kP /home/. | awk 'NR>1 {print $5}'`
if [ ${percent%*%} -gt 80 ]; then
  echo "exceeds"
else
  echo "ok"
done

Or
Code:
if [ `df -kP /home/. | (read _; read _ _ _ _ percent _; echo  ${percent%*%})` -gt 80 ]
then
  echo "exceeds"
else
  echo "ok"
fi

The NR>1 or the read _ skip the first line (header).
# 6  
Old 03-14-2016
Code:
if [ $( df -kP /home | awk 'NR>1 {print $5}' ) -gt 80 ]; then
                  echo "exceeds"
               else
                   echo "don't"
               fi

this might work if we can remove the % sign..
can't we remove without storing into a variable?
IF not then as per ur first suggestion,
if [ percentage -gt 80 ]; then
echo "exceeds";
else
echo "dont "
fi

this will work anyway right?
# 7  
Old 03-14-2016
How about
Code:
df -kP /home | awk 'NR>1 {print ($5+0 > 80)?"exceeds":"doesn''t"}'

Last edited by RudiC; 03-14-2016 at 07:22 AM.. Reason: typo corrected: $5+1 --> $5+0
This User Gave Thanks to RudiC For This Post:
Shreyas N
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