Split line in 4 parts


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# 1  
Split line in 4 parts

Hi Guys,

I have file A.txt

Code:
1
2
3
4
5
6
7
8
9
10
11

Want Output :-

Code:
1 2 3
4 5 6
7 8 9
10 11

I have tried Below Code but Only work for first few lines.
Code:
sed '1,3d;N;s/\n/ /'

Thanks
# 2  
Hello pareshkp,

Following may help you in same.
1st: By using xargs as follows.
Code:
xargs -n3 <  Input_file

Output will be as follows.
Code:
1 2 3
4 5 6
7 8 9
10 11

2nd: By using awk solution.
Code:
awk '{ORS=NR%3==0?"\n":" "} 1'  Input_file

Output will be as follows.
Code:
1 2 3
4 5 6
7 8 9
10 11

Hope this helps you.

Thanks,
R. Singh
# 3  
With the awk suggestion there may be a missing newline at the end, rendering the output an improper Unix format. This could be corrected:
Code:
awk 'END{if(NR%3) printf RS} {ORS=NR%3?FS:RS}1'

--
And for completeness, the inevitable :
Code:
paste -d" " - - - < file

is another one
# 4  
Or with:
bash code:
  1. #!/bin/bash
  2. STR="1
  3. 2
  4. 3
  5. 4
  6. 5
  7. 6
  8. 7
  9. 8
  10. 9
  11. 10
  12. 11"
  13.  
  14. NR=2 ## 0, 1 , 2 = 3 items in a row
  15. C=0
  16.  
  17. for n in $STR;do
  18.     if &#91; $C -eq $NR ]
  19.     then    printf "%s\n" "$n"
  20.     else    printf "%s " "$n"
  21.     fi
  22.     ((C++))
  23.     &#91; $C -gt $NR ] && C=0
  24. done
  25. printf "\n"
  26. exit 0

hth
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